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The limiting reactant is salicylic acid (C₇H₆O₃).
Explanation:
We have the following chemical reaction where salicylic acid (C₇H₆O₃) reacts with acetic anhydride (C₄H₆O₃) to form acetylsalicylic acid (C₉H₈O₄) and acetic acid (C₂H₄O₂):
C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + C₂H₄O₂
We have started with 70.0 g of salicylic acid (C₇H₆O₃) and 80.0 g acetic anhydride (C₄H₆O₃).
First we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of salicylic acid = 70 / 138 = 0.507 moles
number of moles of acetic anhydride = 80 / 102 = 0.784 moles
We see from the chemical reaction that 1 mole of acetic anhydride (C₄H₆O₃) reacts with 1 mole of salicylic acid (C₇H₆O₃) so 0.784 moles of acetic anhydride (C₄H₆O₃) will react with 0.784 mole of salicylic acid (C₇H₆O₃) but we only have 0.507 moles of salicylic acid (C₇H₆O₃). The limiting reactant is salicylic acid (C₇H₆O₃).
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limiting reactant
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Answer:
3 × 10¹⁰⁹
Explanation:
2Cr (s) → 2Cr³⁺ + 6e⁻
and,
Ec° for the above reaction = 0.74 V
also,
3Cu²⁺ (aq) + 6e⁻ → 3Cu(s)
and,
Ea° for the above reaction = 0.34 V
Now,
The cell potential, E° = 0.34 + 0.74 = 1.08
E° = 
thus,
0.34 = 
here, n is the number of electrons exchanged
n = 6
1.08 = 
or
㏒ k = 109.44
taking anti-log both sides
we get
k = 3 × 10¹⁰⁹
Hence, the answer is option (A) 3 × 10¹⁰⁹
19.6 is your answer hope this is right