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saveliy_v [14]
3 years ago
10

One railroad car rolls towards another. Describe the properties of the first car that determine its momentum and how it would im

part an impulse to the second car.
Physics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

Explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

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3 years ago
A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h
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v_{2}=3.5 m/s

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Using the conservation of energy we have:

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v=\sqrt{2gh}

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Therefore the speed of the block after the collision is v_{2}=3.5 m/s

I hope it helps you!

       

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An electron with charge −e and mass m moves in a circular orbit of radius r around a nucleus of charge Ze, where Z is the atomic
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Answer:

v=\sqrt{\frac{kZe^2}{mr}}

Explanation:

The electrostatic attraction between the nucleus and the electron is given by:

F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2} (1)

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k is the Coulomb's constant

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r is the distance between the electron and the nucleus

This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

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k\frac{Ze^2}{r^2}=m\frac{v^2}{r}

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6 0
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