Question

90 points whats the equation for how fast something will be traveling before it hits the ground. How to do the equation PLEASE EXPLAIN here is an example problem
A 0.05 kg-coin is dropped from the top of a skyscraper that is 100 meters high. How fast is the coin traveling just before it hits the ground?
use GPE=M*g*h
KE= 0.5*Mass *velocity squared

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Answer 1

⭐Hey

⭐Here we can use the formula for the body that is in free fall state. .

⭐that is

↪V = underoot 2*g*h

↪So the velocity will be ...

↪V = underoot 2 * 10 * 100

↪V = underoot 2000

↪V = 20 *underoot 5

↪V = 20 ( 2.23)

↪V = 44.6 m/s

Answer 2

You wrote the whole answer right there !

The GPE it has when it's dropped IS exactly the KE it has when it hits the ground.  So you just write (KE at the bottom) = (GPE at the top).

Like this:   M · g · h  =  (1/2) · m · v²

Divide each side by M :

g · h  =  (1/2) · v²

Multiply each side by 2 :

2 · g · h  =  v²

Take the square root of each side:

Speed = √(2 · g · h)

What things do you know in this equation ?

-- 'g' is 9.81 m/s².  

-- 'h' is the height it dropped from.  

-- You know what '2' is.

-- You know how to do a square root on your calculator.

-- Pluggum all in, and you have the speed when it hits the ground.

Notice that the mass of the object went away !   It doesn't matter whether it's a coin or a car.  It only depends on gravity and the height it's dropped from.