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givi [52]
3 years ago
7

90 points whats the equation for how fast something will be traveling before it hits the ground. How to do the equation PLEASE E

XPLAIN here is an example problem
A 0.05 kg-coin is dropped from the top of a skyscraper that is 100 meters high. How fast is the coin traveling just before it hits the ground?
use GPE=M*g*h
KE= 0.5*Mass *velocity squared

message me for questions
Physics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0
⭐Hey

⭐Here we can use the formula for the body that is in free fall state. .

⭐that is

↪V = underoot 2*g*h

↪So the velocity will be ...

↪V = underoot 2 * 10 * 100

↪V = underoot 2000

↪V = 20 *underoot 5

↪V = 20 ( 2.23)

↪V = 44.6 m/s
qwelly [4]3 years ago
3 0

<em>You wrote the whole answer right there !</em>

The GPE it has when it's dropped IS exactly the KE it has when it hits the ground.  So you just write (KE at the bottom) = (GPE at the top).

Like this:   M · g · h  =  (1/2) · m · v²

Divide each side by M :

g · h  =  (1/2) · v²

Multiply each side by 2 :

2 · g · h  =  v²

Take the square root of each side:

<em>Speed = √(2 · g · h)</em>

What things do you know in this equation ?

-- 'g' is 9.81 m/s².  

-- 'h' is the height it dropped from.  

-- You know what '2' is.

-- You know how to do a square root on your calculator.

-- Pluggum all in, and you have the speed when it hits the ground.

Notice that the mass of the object went away !   It doesn't matter whether it's a coin or a car.  It only depends on gravity and the height it's dropped from.

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In a simple RC circuit, at t=0 the switch is closed with the capacitor uncharged. If C=30µF, =50V and R=10k, what is the poten
sergij07 [2.7K]

Answer:

Voltage across the capacitor is 30 V and rate of energy across the capacitor is 0.06 W

Explanation:

As we know that the current in the circuit at given instant of time is

i = 2.0 mA

R = 10 k ohm

now we know by ohm's law

V = iR

V = (2 mA)(10 kohm)

V = 20 volts

so voltage across the capacitor + voltage across resistor = V

V_c + 20 = 50

V_c = 30 V

Now we know that

U = \frac{q^2}{2C}

here rate of change in energy of the capacitor is given as

\frac{dU}{dt} = \frac{q}{C} \frac{dq}{dt}

\frac{dU}{dt} = (30)(2 mA)

\frac{dU}{dt} = 0.06 W

3 0
3 years ago
Why forces are balanced and unbalanced? need help with this the lesson is tommorow
Naya [18.7K]
"Balanced" means that if there's something pulling one way, then there's also
something else pulling the other way. 

-- If there's a kid sitting on one end of a see-saw, and another one with the
same weight sitting on the other end, then the see-saw is balanced, and
neither end goes up or down.  It's just as if there's nobody sitting on it.

-- If there's a tug-of-war going on, and there are 300 freshmen pulling on one
end of a rope, and another 300 freshmen pulling in the opposite direction on
the other end of the rope, then the hanky hanging from the middle of the rope
doesn't move.  The pulls on the rope are balanced, and it's just as if nobody
is pulling on it at all.

-- If a lady in the supermarket is pushing her shopping cart up the aisle, and her
two little kids are in front of the cart pushing it in the other direction, backwards,
toward her.  If the kids are strong enough, then the forces on the cart can be
balanced. Then the cart doesn't move at all, and it's just as if nobody is pushing
on it at all.

From these examples, you can see a few things:

-- There's no such thing as "a balanced force" or "an unbalanced force".
It's a <em><u>group</u> of forces</em> that is either balanced or unbalanced.

-- The group of forces is balanced if their strengths and directions are
just right so that each force is canceled out by one or more of the others.

-- When the group of forces on an object is balanced, then the effect on the
object is just as if there were no force on it at all.
4 0
3 years ago
Read 2 more answers
please help! find magnitude and direction (the counterclockwise angle with the +x axis) of a vector that is equal to a + c
-BARSIC- [3]

Answer:

Option (2)

Explanation:

From the figure attached,

Horizontal component, A_x=A\text{Sin}37

A_x=12[\text{Sin}(37)]

     = 7.22 m

Vertical component, A_y=A[\text{Cos}(37)]

    = 9.58 m

Similarly, Horizontal component of vector C,

C_x  = C[Cos(60)]

     = 6[Cos(60)]

     = \frac{6}{2}

     = 3 m

C_y=6[\text{Sin}(60)]

    = 5.20 m

Resultant Horizontal component of the vectors A + C,

R_x=7.22-3=4.22 m

R_y=9.58-5.20 = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

R=\sqrt{(R_x)^{2}+(R_y)^2}

   = \sqrt{(4.22)^2+(4.38)^2}

   = \sqrt{17.81+19.18}

   = 6.1 m

Direction of the resultant will be towards vector A.

tan(∠COB) = \frac{\text{CB}}{\text{OB}}

                  = \frac{R_y}{R_x}

                  = \frac{4.38}{4.22}

m∠COB = \text{tan}^{-1}(1.04)

             = 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

6 0
3 years ago
A flute plays a note with a frequency of 266 Hz. What is the speed of sound if the wavelength is 1.3 m?
hjlf

Wave speed  =  (frequency)  x  (wavelength)

                       =  (266 /sec)  x  (1.3 meters)

                       =     345.8 meters/sec
6 0
3 years ago
Read 2 more answers
Coiling wire around an iron core and applying an electric current through the wire creates a temporary magnet called an electrom
Serggg [28]

Answer:

C) Use a battery with more voltage.

Explanation:

The equation for the magnetic field around a coil is given by,

B = μ₀NI

where,

B = Magnetic flux density

μ₀ = permeability

N = number of turns per meter

I = Current in the wire

So when using a higher voltage battery, more current passes through the battery as resistance of the wire remains the same.

5 0
2 years ago
Read 2 more answers
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