The water portion of Earth; one of the traditional subdivisions of Earth’s physical environment

A goldfish is capable of seeing which electromagnetic wave?

Leno4ka [110]

Answer:

D

Explanation:

they can see this along with many other fish.

6 0

3 years ago

. Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 1.00 × 104 kg. The thrust of its engin

Viktor [21]

Answer:

a) The module's acceleration in a vertical takeoff from the Moon will be $1.377 \frac{m}{s^2}$

b) Then we can say that a thrust of $3*10^{4} N$ won't be able to lift off the module from the Earth because it's smaller than the module's weight ( $9.8 *10^{4} N$ ).

Explanation:

a) During a vertical takeoff, the sum of the forces in the vertical axis will be equal to mass times the module's acceleration. In this this case, the thrust of the module's engines and the total module's weight are the only vertical forces. (In the Moon, the module's weight will be equal to its mass times the Moon's gravity acceleration)

$T-(m*g)=m*a$

Where:

$T=$ thrust $=3 *10^{4} N$

$m=$ module's mass $=1 *10^{4} N$

$g=$ moon's gravity acceleration $=1.623 \frac{m}{s^2}$

$a=$ module's acceleration during takeoff

Then, we can find the acceleration like this:

$a=\frac{T}{m} -g=\frac{3*{10}^4 N}{1*{10}^4 kg}-1.623\frac{m}{s^2}$

$a=1.377 \frac{m}{s^2}$

The module's acceleration in a vertical takeoff from the Moon will be $1.377 \frac{m}{s^2}$

b) To takeoff, the module's engines must generate a thrust bigger than the module's weight, which will be its mass times the Earth's gravity acceleration.

$weight=m*g=(1*{10}^4 kg)*(9.8 \frac{m}{s^2})=9.8 *10^{4} N$

Then we can say that a thrust of $3*10^{4} N$ won't be able to lift off the module from the Earth because it's smaller than the module's weight ( $9.8 *10^{4} N$ ).

8 0

4 years ago

At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring sets the full bunch of banan

olga55 [171]

Answer:

Mass of banana is $1.12$ Kg

Explanation:

Step 1: Determine the equation of speed of an object moving in an harmonic motion

Speed of moving in an harmonic motion is given by

$v = \sqrt{\frac{k}{m} (A^2 -x^2)} \\$

Here, v represents the speed of the object in harmonic motion, k is the springs constant, m is the mass of the object, A is the amplitude, and x is the position.

In this question , $x = 0$ because only at this position maximum speed occurs

So the simplified equation becomes -

$v = \sqrt{(\frac{k}{m} * A)}$

OR

$m = \frac{kA^2}{v_(max)^2}$

Substituting the given values in above equation we get -

Assume spring constant is $16$ N/m

$m = \frac{16 * 0.14}{2} \\m = 1.12$

Mass of banana is $1.12$ Kg

5 0

3 years ago

If there is "waste" energy, does the Law of Conservation of Energy still apply? please don't type something random if so i'll ju

FinnZ [79.3K]

Explanation:

Yes, the law of conservation of energy still applies even if there is waste energy.

The waste energy are the transformation products of energy from one form to another.

According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".

But of then times, energy is lost as heat or sound within a system.

If we take into account these waste energy, we can see that energy is indeed conserved.
The sum total of the energy generated and those produced will be the same if we factor in other forms in which the energy has been transformed into.

8 0

3 years ago

Define force and provide an example

ollegr [7]

Answer:

force-strength,power or energy as an attribute of motion, movement or action. Example: Frictional force.

4 0

4 years ago