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Ne4ueva [31]
3 years ago
5

What form the ideal gas law would you use to calculate the temperature of a gas

Chemistry
1 answer:
Charra [1.4K]3 years ago
4 0

You can use any form of the Ideal Gas Law, but usually one form is more convenient, depending on the information given.

There are three forms of the Ideal Gas Law.

Form 1

P V = n R T

If the question gives you the number of moles  then

, this is the most convenient one to use.

Form 2

P V = m M R T , where  m  is the mass of the gas and  

M  is its molar mass.

If the question gives you the mass  

m

, this is the most convenient one to use.

Form 3

P  = ρ M R T , where  ρ  is the density of the gas.   If the question gives you the density  

ρ , this is the most convenient one to use.

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Is the volume of water measured using the graduated cylinder identical to the volume calculated
tatuchka [14]
<h2>Answer:</h2>

The volume of water measured using the graduated cylinder is <em>not exactly identical </em> identical to the volume calculated.

<h3>Explanation:</h3>

Calculated volume is theoretical value calculated from the density and mass of water.

But volume measured in cylinder can contain the personal error of individual.

Because in graduated cylinder volume is measured in a specific way that is:

  • Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid.
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3 0
4 years ago
Find the mass of calcium oxide produced from the thermal decomposition of 50 g of calcium carbonate.
anastassius [24]

Answer:

28 g

Explanation:

The chemical equation of the reaction is given below:

CaCO₃ (s) ⇒ CaO (s) + O₂ (g)

From the chemical equation, 1 mole of CaCO₃ produces 1 mole of CaO.

So, we find the number of moles,n of  CaCO₃ in 50 g from

n = m/M where n = number of moles of  CaCO₃, m = mass of CaCO₃ and M = molar mass of CaCO₃ = 40 g/mol + 12 g/mol + 3 × 16 g/mol = 52 g/mol + 48 g/mol = 100 g/mol

So, n = m/M

= 50 g/100 g/mol

= 0.5 mol

Since From the chemical equation, 1 mole of CaCO₃ produces 1 mole of CaO, then 0.5 × 1 mole of CaCO₃ produces 0.5 × 1 mole of CaO, which is 0.5 mole of CaCO₃ produces 0.5 mole of CaO.

So, we have 0.5 mol of CaO.

We find the mass of CaO from

n =m'/M' where n = number of moles of CaO = 0.5, m' = mass of CaO and M' = molar mass of CaO = 40 g/mol + 16 g/mol = 56 g/mol

So, m' = nM'

= 0.5 mol × 56 g/mol

= 28 g

3 0
3 years ago
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