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r-ruslan [8.4K]
3 years ago
6

The government, through the FCC (Federal Communications Commission), has set rules and guidelines for the use of radio equipment

to better control wireless frequency "traffic".
A wireless server gives off 3.3 X 10-24 joules of energy. What is the wavelength of this server in meters?
Answer
A 22x10-57 m
B 60 X 10-52 m
5.0 X 100m
D 9.1 X1031m
Chemistry
1 answer:
Doss [256]3 years ago
5 0

Answer:

Wavelength = 0.06024 m

Explanation:

Equation of energy of wavelength from Einstein's relativity equation is;

E = hc/λ

Where;

h is Planck's constant = 6.626 × 10⁻³⁴ J. s

c is speed of light = 3 × 10⁸

We are given E = 3.3 × 10^(-24) J

Making wavelength λ the subject, we have;

λ = hc/E

Thus;

(6.626 × 10⁻³⁴ × 3 × 10⁸)/(3.3 × 10^(-24)) = 6.024 × 10^(-2) = 0.06024 m

Wavelength = 0.06024 m

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2 years ago
After careful analysis, an electromagnetic wave is found to have a frequency of 7.8 x 10^6 Hz. What is the speed of the wave?
damaskus [11]

Answer:

 

Explanation:

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3 years ago
Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0
2 years ago
The energy of a photon needed to cause ejection of an electron from a photoemissive metal is expressed as the sum of the binding
slega [8]

Answer:

Binding\ energy=43.43\times 10^{-20}\ J

Explanation:

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E=h\nu_0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

\nu_0=\frac {c}{\lambda_0}

Applying the equation as:

\frac {h\times c}{\lambda}=\frac {hc}{\lambda_0}+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light being bombarded

Given, \lambda=4.00\times 10^{-7}\ m

\frac {hc}{\lambda_0} is the binding energy or threshold energy

\frac {1}{2}\times m\times v^2 is the kinetic energy of the electron emitted.  = 6.26\times 10^{-20}\ J

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\frac{h\times c}{\lambda}=Binding\ Energy+Kinetic\ Energy

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\frac{19.878}{10^{19}\times \:4}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

49.69\times 10^{-20}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

Binding\ energy=43.43\times 10^{-20}\ J

5 0
3 years ago
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hope this helps!

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3 0
3 years ago
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