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r-ruslan [8.4K]
3 years ago
6

The government, through the FCC (Federal Communications Commission), has set rules and guidelines for the use of radio equipment

to better control wireless frequency "traffic".
A wireless server gives off 3.3 X 10-24 joules of energy. What is the wavelength of this server in meters?
Answer
A 22x10-57 m
B 60 X 10-52 m
5.0 X 100m
D 9.1 X1031m
Chemistry
1 answer:
Doss [256]3 years ago
5 0

Answer:

Wavelength = 0.06024 m

Explanation:

Equation of energy of wavelength from Einstein's relativity equation is;

E = hc/λ

Where;

h is Planck's constant = 6.626 × 10⁻³⁴ J. s

c is speed of light = 3 × 10⁸

We are given E = 3.3 × 10^(-24) J

Making wavelength λ the subject, we have;

λ = hc/E

Thus;

(6.626 × 10⁻³⁴ × 3 × 10⁸)/(3.3 × 10^(-24)) = 6.024 × 10^(-2) = 0.06024 m

Wavelength = 0.06024 m

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Part A Which acid in each of the following pairs has the stronger conjugate base? Match the words in the left column to the appr
vichka [17]

Answer:

HF

H₂S

H₂CO₃

NH₄⁺

Explanation:

<em>Which acid in each of the following pairs has the stronger conjugate base?</em>

According to Bronsted-Lowry acid-base theory, <em>the weaker an acid, the stronger its conjugate acid</em>. Especially for weak acids, pKa gives information about the strength of such acid. <em>The higher the pKa, the weaker the acid.</em>

<em />

  • Of the acids HCl or HF, the one with the stronger conjugate base is HF because it is a weak acid.
  • Of the acids H₂S or HNO₂, the one with the stronger conjugate base is    H₂S  because it is a weaker acid. pKa (H₂S) = 7.04 > pKa (HNO₂) = 3.39
  • Of the acids H₂CO₃ or HClO₄, the one with the stronger conjugate base is H₂CO₃ because it is a weak acid.
  • Of the acids HF or NH₄⁺, the one with the stronger conjugate base is NH₄⁺ because it is a weaker acid. pKa (HF) = 3.17 < pKa (NH₄⁺) = 9.25
6 0
3 years ago
Calculate the ΔG°rxn using the following information at 298K. 2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l) ΔG°rxn = ? ΔH°f (kJ/mol) -2
Mkey [24]

Answer:

ΔG°rxn = +50.8 kJ/mol

Explanation:

It is possible to obtain ΔG°rxn of a reaction at certain temperature from ΔH°rxn and S°rxn, thus:

<em>ΔG°rxn = ΔH°rxn - T×S°rxn (1)</em>

In the reaction:

2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l)

ΔH°rxn = 3×ΔHfNO2 + ΔHfH2O - (2×ΔHfHNO3 + ΔHfNO)

ΔH°rxn = 3×33.2kJ/mol + (-285.8kJ/mol) - (2×-207.0kJ/mol + 91.3kJ/mol)}

ΔH°rxn = 136.5kJ/mol

And S°:

S°rxn = 3×S°NO2 + S°H2O - (2×S°HNO3 + S°NO)

ΔH°rxn = 3×0.2401kJ/molK + (0.0700kJ/molK) - (2×0.146kJ/molK + 0.2108kJ/molK)

ΔH°rxn = 0.2875kJ/molK

And replacing in (1) at 298K:

ΔG°rxn = 136.5kJ/mol - 298K×0.2875kJ/molK

<em>ΔG°rxn = +50.8 kJ/mol</em>

<em />

7 0
3 years ago
Read 2 more answers
What would happen if I removed a resistor from a parallel circuit? What would
barxatty [35]

Answer:

In a parallel circuit, current divides through resistors and current might be different depending upon the resistor and all resistors have the same potential difference. Therefore, if a parallel resistor was removed then the total resistance of the circuit will increase.

7 0
2 years ago
Help me please thank you
ankoles [38]

Answer:

When nitric acid combine with sodium hydroxide the salt formed is called sodium nitrate. option B

Explanation:

It is the strong acid strong base reaction. When acid and base react with each other salt and water are formed.

In given reaction  nitric acid combine with sodium hydroxide base and form sodium nitrate salt and water.

Chemical equation:

HNO₃(aq) + NaOH(aq)       →      NaNO₃(aq) + H₂O(l)

Ionic equation:

H⁺NO₃⁻(aq) + Na⁺OH⁻(aq)       →      Na⁺NO₃⁻(aq) + H₂O(l)

Net ionic equation:

H⁺(aq) + OH⁻(aq)   →   H₂O(l)

The Na⁺(aq) and NO₃⁻(aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

3 0
3 years ago
1(a). What is the solubility of calcium chloride (CaCl2) at 5°C?
In-s [12.5K]

Answer:

60 g/100 g water  

Explanation:

Find 5 °C on the horizontal axis.

Draw a line vertically from that point until you reach the solubility curve for CaCl₂.  

Then draw a horizontal line from there to the vertical axis.

The solubility of CaCl₂ is 60 g/100 g water.

7 0
3 years ago
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