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Lostsunrise [7]
3 years ago
11

Consider the reaction pathway graph below.

Chemistry
2 answers:
barxatty [35]3 years ago
5 0
Correct Answer: option 4: <span>E and D show that the energy of the products is less than that of the reactants.

Reason: 
For the reaction:          Q + R      </span>→        N + M
<span>                                  (reactant)             (product)

From the graph, it is clearly evitable that E represent energy of reactant, while D represents energy of products. Also, value of D is less as compared to E. This signifies that, products (N+M) has less energy as compared to reactants (Q+R). Also, the reaction is exothermic in nature. 
</span>
ZanzabumX [31]3 years ago
3 0
<span>Answer: the fourth option: E and D show that the energy of the products is less than that of the reactants.


Explanation:
</span><span />

<span>The graph shows how the energy of the species (vertical axis) changes as the reaction progress (horizontal axis).
</span><span />

<span>We can see each option:
</span><span />

<span>1) A and C show that the reaction enthalpy is less than the activation energy.
</span><span />

<span>FALSE: C is the energy difference between products and reactants, and that is the enthalpy of the reaction, while C is the activation energy (the peak of the curve).


2) G and E show that this reaction is an endothermic process with heat release.
</span><span />

<span>FALSE: since G is below E, the final energy is less than the initial energy, meaning that the reaction released energy and, consequently, the reaction is exhotermic.


3) B and F show that the activated complex has less energy than the reactants.
</span><span />
FALSE
<span>The activated complex is at the peak of the curve, so it hass more energy than the reactants.
</span><span />

<span>4) E and D show that the energy of the products is less than that of the reactants.

</span><span>TRUE: indeed D is below E meaning the the energy of the products (D) is less than the energy of the reactants (E).</span>

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Answer:

The concentration of NaOH solution is 3,65M

Explanation:

The neutralization of NaOH with HCl is:

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12,67 mL ≡ 0,01267L×\frac{2,74 moles}{1L} = <em>0,0347 moles HCl </em>≡ 0,0347 moles NaOH

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13,65 mL - 4,50 mL = <em>9,50 mL </em>≡ 0,0095L

Thus, the concentration of NaOH solution is:

\frac{0,0347 moles}{0,0095L} = <em>3,65M</em>

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