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Tom [10]
2 years ago
11

Limitations of paper chromatography​

Chemistry
2 answers:
Ksju [112]2 years ago
5 0

Answer:

Limitations of paper chromatography​ is described below in complete details.

Explanation:

Limitations of Paper Chromatography

  • A huge number of representations cannot be employed in paper chromatography.
  • In a quantitative investigation, paper chromatography is not sufficient.
  • The complex compound cannot be separated by paper chromatography.
  • Less Accurate correlated to HPLC or HPLC.

castortr0y [4]2 years ago
4 0

Answer:

Limitations of Paper Chromatography.

1.Large quantity of sample cannot be applied on paper chromatography.

2.In quantitative analysis paper chromatography is not effective.

3.Complex mixture cannot be separated by paper chromatography.

4.Less Accurate compared to HPLC or HPTLC.

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During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
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Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

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V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

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