Answer:
The velocity will be v1 = 0.58[m/s]
Explanation:
This problem can be solved by the law of conservation of the moment, which explains that the moment of a system remains constant because there are no external forces acting on it.
We have the following initial data:
m1 = mass of the skater = 55 [kg]
m2 = mass of the ball = 3 [kg]
v2 = velocity of the ball = 8 [m/s]
Therefore:
![m_{1}*v_{1}+m_{2}*v_{2}=m_{1}*v_{1}+m_{2}*v_{2}\\(50*0)+(3*0)=(50*v_{1})+(3*8)\\50+3-24=50*v_{1}\\v_{1}= 0.58[m/s]](https://tex.z-dn.net/?f=m_%7B1%7D%2Av_%7B1%7D%2Bm_%7B2%7D%2Av_%7B2%7D%3Dm_%7B1%7D%2Av_%7B1%7D%2Bm_%7B2%7D%2Av_%7B2%7D%5C%5C%2850%2A0%29%2B%283%2A0%29%3D%2850%2Av_%7B1%7D%29%2B%283%2A8%29%5C%5C50%2B3-24%3D50%2Av_%7B1%7D%5C%5Cv_%7B1%7D%3D%200.58%5Bm%2Fs%5D)
<span> is located between the fulcrum and the resistance force -direction of force does
</span>
pressure absolute = pressure gage + pressure atmosphere
Answer:
r = 0.491 m
Explanation:
In this case the System is formed by the teacher with the two masses, so the forces during movement are internal and the angular momentum is conserved
Initial.
L₀ = I₀ w₀
Final
Lf = I w
L₀ = Lf
I₀ w₀ = I w
The moment of inertia is
I₀ = m r₀²
I = m r²
Let's replace
m r₀² w₀ = m r² w
r² = r₀² w₀ / w
Angular velocity
w₀ = 10 rpm (2pi rad / 1 rev) (1 min / 60 s) = 1.047 rad / s
w = 32.5 rpm = 3.403 rad / s
Let's calculate
r = √(0.785 1.047 / 3.403)
r = 0.491 m
The appropriate response is the Unusual climate. These are eccentric serious or unseasonal climate; climate at the extremes of the authentic circulation—the range that has been found before. Regularly, extraordinary occasions depend on an area's recorded climate history and characterized as lying in the most strange 10%.
