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2 years ago

11

What is the difference between hypothesis, theory and scientific law?

1 answer:

patriot [66]2 years ago

5 0

Hypothesis is what you think will happen , a theory is a system of ideas to explain something. scientific law means a statement that is based on repeated experimental observations.

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Driving home from school one day, you spot a ball rolling out into the street (Figure 5-21). You brake for 1.20 s, slowing your

frosja888 [35]

A ) v = v o + a t ( the acceleration will be negative )
9.50 = 16.0 + a * 1.2
a * 1.2 = -16.0 + 9.50
a * 1.2 = - 6.5
a = - 6.5 : 1.2
a = - 5.4167 m/s²
F = m * a = 950 kg * 5.4167 m/s²
F = 5,145.8 N ( the average force exerted on a car during braking )
b ) d = v o - a t² / 2
d = 16.0 * 1.2 - ( 5.4167 * 1.2² / 2 ) =
= 19.20 - 3.90 = 15.30 m

7 0

3 years ago

A shot is projected at an angle of 55 to the horizontal with a velocity of of 10m/s. Calculate 1. the highest point reached 2. T

il63 [147K]

Answer:

my gess g=10m/s

Explanation:

5 0

2 years ago

An electron has an initial velocity of (19.0 j + 18.0 k) km/s and a constant acceleration of (3.00 ✕ 1012 m/s2)i in a region in

asambeis [7]

Answer:

$E=(-17.08 i +7.2 j -7.6 k )N/C$

Explanation:

$v= (19.0j+18.k)km/s$

$a=3.0x10^{13}m/s^2$

$\beta= 400x10{-6}T$

Electron information needed to solve the question:

$m_e=9.11x10^{-31}kg$

$q=-1.6x10{-19}C$

$F=F_E+F_B=q*(E+Vx \beta)$

$F=m*a$

$m*a=q*(E+Vx\beta)$

$E=\frac{m*a}{q}-(Vx\beta )$

$E=\frac{9.11x10{-31}kg*3.0x10^{12}m/s^2}{-1.6x10{-19}C}-[(19.0x10^3mj+18.0x10^3m)xi(400x10^{-6}T)]$

$E=-i17.08N/C-[7.6(-k)+7.2(j)]N/C$

$E=(-17.08 i +7.2 j -7.6 k )N/C$

6 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Natasha_Volkova [10]

Ok srry bout last time but the answer is A) kelvin: time the reason is because everything else is a SI. Hope this helps and TURTLE

7 0

3 years ago

Read 2 more answers

Suppose the odometer on our car is broken and we want to estimate the distance driven over a 30 second time interval. We take th

Natalija [7]

Let say for every 5 s of time interval the speed will remain constant

so it is given as

v(mi/h) 16 21 23 26 33 30 28

now we have to convert the speed into ft/s as it is given that 1 mi/h = 5280/3600 ft/s

so here we will have

v(ft/s) 23.5 30.8 33.73 38.13 48.4 44 41.1

now for each interval of 5 s we will have to find the distance cover for above interval of time

$d = v \times t$

$d = (23.5 + 30.8 + 33.73 + 38.13 + 48.4 + 44 + 41.1) \times 5$

$d = 1298.1 ft$

so here it will cover 1298.1 ft distance in 30 s interval of time

4 0

3 years ago

Read 2 more answers