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3 years ago

9

When used as an energy source in a nuclear power plant, uranium is burned in a similar way as one would burn wood or coal for en

ergy.
a. True
b. False

1 answer:

zavuch27 [327]3 years ago

3 0

False because nuclear fission is used on uranium in nuclear power station and this reaction is continuous since a neutron hits a uranium atom and splits it. Then 2-3 neutrons are released which continues the cycle or hitting other uranium atoms. If this reaction isn't contained, it could get out of control and become a nuclear bomb. So it can't be burned like wood nor coal.
Hope this is helpful. <span />

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A rocket car is developed to break the land speed record along a salt flat in Utah. However, the safety of the driver must be co

Naddika [18.5K]

Answer:

a = 45 m/s/s

Explanation:

As we know that total mass of the rocket is

$M = 6000 kg$

total mass of the fuel is given as

$m = 2000 kg$

all the fuel is burnt in 15 s

so rate of the fuel burning is given as

$\frac{dm}{dt} = \frac{2000}{15}$

$\frac{dm}{dt} = 133.33 kg/s$

now the thrust force on the rocket is given as

$F_{th} = v\frac{dm}{dt}$

$(6000 - 133.33 t) a = (900 + v)(133.33)$

so we have

$\frac{dv}{900 + v} = (133.33)\frac{dt}{6000 - 133.33 t}$

so we have

$ln(\frac{900 + v}{900}) = - ln(\frac{6000 - 133.3 t}{6000})$

$1 + \frac{v}{900} = \frac{6000}{6000 - 133.3 t}$

now acceleration is rate of change in velocity

$\frac{1}{900}\frac{dv}{dt} = \frac{133.3\times 6000}{(6000 - 133.3t)^2}$

so acceleration at t = 15 s

$a = 45 m/s^2$

3 0

4 years ago

calculate the period of a wave whose frequency is 5 Hz and whose wavelength is 1 cm give your answer in decimal form

Pavlova-9 [17]

Period T = 1/f, where f = frequency = 5 Hz

T = 1/5 = 0.20 s

Period = 0.20 seconds.

8 0

3 years ago

Read 2 more answers

A particle begins to move with uniform acceleration. If in the first second it travels 3m

nataly862011 [7]

Answer:6m

Explanation:

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3 years ago

A uniform solid sphere of mass M and radius R is free to rotate about a horizontal axis through its center. A string is wrapped

LenaWriter [7]

Answer:

$a = \frac{mg}{m + \frac{2}{5}M}$

Explanation:

To calculate the Acceleration and the tension of the object, we start by considering the value of the Tension through its moment of Inertia and Acceleration based on the angular velocity

$\tau = I\alpha = Tension(T)*R$

And $a = \alpha R$

Replacing,

$T*R = I\alpha = (\frac{2}{5} MR^2)*\frac{a}{R})\\T*R = \frac{2}{5}MaR\\T = \frac{2}{5}Ma$

The following forces occur in the body,

$mg - T = ma$

By this way we have the acceleration

$mg - \frac{2}{5}Ma = ma$

$a(m + \frac{2}{5})M) = mg$

$a = \frac{mg}{m + \frac{2}{5}M}$

6 0

4 years ago

State ohm’s law Q.34.7

defon

Ohm's law states that: $V=RI$

Explanation:

Ohm's law states that in a conductor, the potential difference across the conductor is directly proportional to the current flowing through it. Mathematically,

$V \propto I$

where

V is the potential difference

I is the current

The constant of proportionality is called resistance (R), and it gives a measure of "how much the conductor opposes" to the flow of current. Therefore Ohm's law can be rewritten as

$V=RI$

where R is the resistance. By rewriting the equation as

$I=\frac{V}{R}$

we see that the larger the resistance, the lower the current in the conductor.

Learn more about Ohm's law:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

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3 years ago