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3 years ago

Please help! This is really confusing.

Mathematics

2 answers:

ioda3 years ago

8 0

39 meters in 3 minutes means 13 meters each minute and 26 meters in two minutes. Multiply by 1,000 to convert it into 26000 millimeters.

frutty [35]3 years ago

6 0

3 minutes=39 meters
2 minutes= x meters

3minutes 2minutes
_________ = ________
39meters x meters

Cross multiply
3x=78
divide both sides by 3
x=26

1m=1000mm
So 26*1000=26000mm

Answer=26000mm

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16 Find the distance between the two points of J(-8, 0) and K(1, 4). Round to the nearest tenth. * (6 Points) O 10.3 o 8.5 O 11.

guajiro [1.7K]

Answer:

9.8

Step-by-step explanation:

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3 years ago

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Talja [164]

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7 0

3 years ago

Read 2 more answers

Answer this equation: 4 3/5 - -3 2/5 + 3

horrorfan [7]

Answer:

Step-by-step explanation:

$4\frac{3}{5} -(-3\frac{2}{5})+3$

Negative and another negative makes a positive.

$4\frac{3}{5}+3\frac{2}{5}+3$

Add the fractions first.

$7\frac{5}{5}+3$

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$8+3$

Add the numbers.

$24$

I hope this helps!

6 0

3 years ago

Read 2 more answers

If the range of f(x)= square root mx and the range of g(x)=m square root x are the same, which statement is true about the value

AveGali [126]

M can be any positive real number.

Explanation:

From f(x) = √(mx) ; if x is posive m has to be positive; if x is negative m has to be negative; if x is cero m can have any value, and the range will always be 0 or positve

From g(x) = m √x; x can only be 0 or positive and the range will have the sign of m.

Given we concluded that the range of f(x) can only be 0 or positive, then me can only be 0 or positive.

3 0

3 years ago

Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago