Answer:
Beryllium-8 (8Be, Be-8) is a radionuclide with 4 neutrons and 4 protons. It is an unbound resonance and nominally an isotope of beryllium. It decays into two alpha particles with a half-life on the order of 10−16 seconds; this has important ramifications in stellar nucleosynthesis as it creates a bottleneck in the creation of heavier chemical elements. The properties of 8Be have also led to speculation on the fine tuning of the Universe, and theoretical investigations on cosmological evolution had 8Be been stable.
Explanation:
Answer:
- <em>the electron configuration for P iin complete form in order of increasing orbital energy is: 1s² 2s² 2p⁶ 3s² 3p³ </em>
Explanation:
As stated, <em>writing the symbol for the occupied subshell and adding a superscript to indicate the number of electrons in that subshell is a common way to represent the electron configuration of the atoms</em>.
There are several rules that you have to follow to write such electron configurations. I will explain the needed to write the electron configuration for the atoms of P (phosphorus) in the requested form.
1) <u>First, determine the number of electrons of the atom</u>:
- Use the atomic number. Phosphorus has atomic number 15.
- The atomic number is the number of protons. So, phosphorus has 15 protons.
- A neutral atom has the same number of electrons than protons. So, phosphorus atoms have 15 electrons.
2)<u> Fill the orbitals in order of incrasing orbital energy</u>
- Aufbau rules are very helpful. As per it this is the order of the orbitals:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶ ...
- 15 electrons ⇒ <u>1s² 2s² 2p⁶ 3s² 3p³</u>
- Check the number of electrons: 2 + 2 + 6 + 2 + 3 = 15
- Hence, that is the electron configuration for P iin complete form in order of increasing orbital energy.
3) Other rules that you must consult to deal with some special issues of the electron configurations are: the exclusion principle of Pauli and the Hund's rule, but they are beyond the interest of this question.
Au^2S^3+ 3H^2 = 2Au + 3H^2S
SInce earths gravitational force is 9.81, and outer space is less than that, the force decreases
618.936 joules. Multiplied by 4.182 though, not much difference, but
