Answer:
=<em><u> 0.42 moles of CO2 </u></em>
Explanation:
From Avogadro's constant
6.02×10^23 molecules are in 1 mole of CO2
2.54×10^23 molecules will be in
=[(2.54×10^23) ÷ (6.02×10^23)]
= 0.42 moles of CO2
I very much Disagree. The esophagus runs from your mouth to your stomach.
Answer:
So the volume will be 2.33 L
Explanation:
The reaction for the combustion is:
2 C₄H₁₀ (g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (l)
mass of butane to moles (mass / molar mass)
1.4 g / 58 g/mol
= 0.024 moles
2 moles of butane can produce 8 moles of carbon dioxide
0.024 moles of butane must produce (0.024 × 8) /2
= 0.096 moles of CO₂
Now we apply the Ideal Gases Law to find out the volume formed.
P . V = n . R . T
p = 1atm
n = 0.096 mol
R = 0.082 L.atm/mol.K
T = 273 + 23 = 296K
V = ?
1atm × V = 0.096 mol × 0.082 L.atm/mol.K × 296K
V = 0.096 mol × 0.082 L.atm/mol.K × 296K / 1atm
= 2.33 L
So the volume will be 2.33 L
<span>0.002 moles is the answer </span>
