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3 years ago

What is the ending for the names of all binary compounds, both ionic and molecular?

Chemistry

2 answers:

viva [34]3 years ago

8 0

it is followed by -ide hope this helps

Andru [333]3 years ago

4 0

it is followed by -ide have a good one

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The density of mercury is 13.5 g/mL and the density of water is 1.00 g/mL. If a mercury barometer reads 677 mmHg, what is the ba

natulia [17]

8 0

3 years ago

A student was assigned the task of determining the identity of an unknown liquid. The student weighed a clean, dry 250-mL Erlenm

LiRa [457]

Answer:

248.4 mL

Explanation:

Erlenmeyer = 78.649 g

Erlenmeyer + Water = 327.039 g

Water = (Erlenmeyer + Water) - Erlenmeyer

Water = 327.039 - 78.649

Water = 248.4 g

if the density of water is 1 g/mL, we can say that each mL of water weigh 1 g, so we have 248.4 mL of water in the Erlenmeyer Flask.

4 0

3 years ago

35.0 mL of 12.0 M HCl is added to enough water to have a final volume of 1.20 L. What is the molarity of the final solution?

creativ13 [48]

<h3>Answer:</h3>

0.35 M

<h3>Explanation:</h3>

<u>We are given;</u>

Initial volume as 35.0 mL or 0.035 L
Initial molarity as 12.0 M
Final volume is 1.20 L

We are required to determine the final molarity of the solution;

Dilution involves adding solvent to a solution to make it more dilute which reduces the concentration and increases the solvent while maintaining solute constant.

Using dilution formula we can determine the final molarity.

M1V1 = M2V2

Rearranging the formula;

M2 = M1V1 ÷ V2

= (12.0 M × 0.035 L) ÷ 1.2 L

= 0.35 M

Thus, the final concentration of the solution is 0.35 M

6 0

3 years ago

A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le

Gnesinka [82]

For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138