All categories

3 years ago

How does charle's law relate to breathing?

2 answers:

6 0

It will change volume as it warms in passing through the sinuses. As the air warms it expands to a larger volume..... because according to Charles law, volume is directly proportional to temperature at constant pressure.

tigry1 [53]3 years ago

5 0

It affects the volume of air you can inhale.

You might be interested in

Select all that apply.

Fed [463]

To improve the efficiency of fireplaces, technologies such as A. addition of catalytic combustors and B. <span>addition of boilers are used in so far. Addition of catalytic combustors hastens the process and makes use of inerts that cannot be used. The addition of boilers also adds to the efficiency by converting fluids to higher temperatures,</span>

7 0

4 years ago

Read 2 more answers

Matching: Which is the control center of the cell that contains DNA?

MissTica

The answer is B. Nucleus

3 0

3 years ago

A sample of hydrogen gas has a pressure of 1.50 atm with a volume of 5.00 L, what is the pressure if the volume is expanded to 7

miss Akunina [59]

Answer:

The pressure is 0,97 atm

Explanation:

We apply Boyle Mariotte's Law, where for a certain mass of gas, at constant temperature, the pressure and volume vary inversely proportionally: P1x V1 = P2 x V2 P2= (P1 x V1)/V2

P2 = 1, 50 atm x 5, 00 L /7,74 L

P2= 0, 97 atm

6 0

3 years ago

When a 500. gram sample of water at 19.0°C absorbs 8400 Joules of heat, the temperature of the water

Westkost [7]

Answer: 23.0ºC

Explanation:

Just trust me

7 0

3 years ago

4) 10.00 mL of sulfuric acid is neutralized in a titration using 18.54 mL of 0.100 M NaOH.

sdas [7]

Answer:

a) $H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

b) $M_{H_2SO_4}=0.0927M$

Explanation:

Hello!

In this case, for this acid-base reaction which also known as a neutralization because sulfuric acid is neutralized with sodium hydroxide, we can write the undergoing chemical reaction as shown below:

$H_2SO_4+NaOH\rightarrow Na_2SO_4+H_2O$

However, it needs to be balanced as two sodium atoms are yielded:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

Next, since there is a 1:2 mole ratio between the acid and the base, at the equivalence point, at which the moles of acid and base are consumed, we write:

$2n_{H_2SO_4}=n_{NaOH}$

Which can also be written in terms of the given volumes and concentration of the base:

$2M_{H_2SO_4}V_{H_2SO_4}=M_{NaOH}V_{NaOH}$

In such a way, we solve for the concentration of sulfuric acid as shown below:

$M_{H_2SO_4}=\frac{M_{NaOH}V_{NaOH}}{2V_{H_2SO_4}} =\frac{18.54mL*0.100M}{2*10.00mL}\\\\ M_{H_2SO_4}=0.0927M$

Best regards!

5 0

3 years ago