Question

A car starts from rest and accelerates at a constant rate. After the car has gone 50 m it has a speed of 21 m/s. What is the acceleration of the car?
O A. 2.4 m/s2
O B. 4.4 m/s2
O C. 5.5 m/s2
O D. 0.23 m/s2

Answer 1

Answer:4.41ms-2

Explanation:

From rest U=0,therefore when given S=50m and V=21m/s then you apply the formula of linear motion which is V^2=U^2+2as

Then substitute for the given values and reach the answer e.g 21^2=(0)^2+2×a×50

441m/s=100ma

a=4.41ms-2