M*U + 0 = m*v'1 + 2m*v'2
the zero means deuteron has no velocity
<span>where v'1 and v'2 are the post-collision velocities.
</span>The equatio becomes
<span>U = v'1 + 2v'2</span>
<span>U = v'2- v'1 </span>
<span>v'2 = U + v'1 </span>
<span>U = v'1 + 2(U + v'1) = 2U + 3v'1 </span>
<span>U = -3V </span>
<span>V = -U / 3 </span>
<span>The speed ratio is 1/3 </span>
<span>B) Since KE is proportional to the square of the speed, if the speed is 1/3, then KE is 1/9 </span>
<span>C) (1/3)ⁿ = 1/729 </span>
<span>3ⁿ = 729 </span>
<span>n = 6 </span>
Answer:
102 m upwards.
Explanation:
Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.
Fixed that work being 1 kJ, we get
Answer:
Summer begins in the Northern Hemisphere on June 20 or 21 when the North Pole is tilted a full 23.5° toward the sun. On this day, the Northern Hemisphere has the most hours of daylight, while the Southern Hemisphere has the least hours of daylight.
Explanation:
Answer:
Explanation:
Total mechanical energy = 1/2 m ω²A² where ω is angular frequency and A is amplitude .
Given
1/2 m ω²A² = 5.46
ω²A² = 2 x 5.6 / m
= 2 x 5.6 / .325
= 34.46
ωA = 5.87
maximum speed = ωA = 5.87 m /s
B )
angular frequency = 2π / T , T is period of oscillation .
= 2 x 3.14 / .22
= 28.54 s⁻¹
ω = 
k is force constant and m is mass
k = 264.72 N/m
C)
ωA = 5.87
28.54 X A = 5.87
A = .2056 m
= 20.56 cm .
Player A needs the least amount of energy. The ball is light weight and she is closest to the goal so the momentum need to kick the ball will be the least and the distance is has to travel is the shortest. But player C needs the most amount of energy. The ball is heavy so it will take the most momentum to move the ball and over such a long distance. Hope this help idrk.
