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qwelly [4]
3 years ago
6

A water-balloon launcher with a mass of 1.75 kg is suspended on a wire. It fires a 1.25 kg balloon to the east at a velocity of

12.0 m/s. What is the resulting velocity of the launcher if the net force on the launcher is equal to the reaction force? O A. 6.1 m/s east B. 16.8 m/s west C. 7.6 m/s west D. 8.6 m/s west​
Physics
1 answer:
poizon [28]3 years ago
8 0

Answer:

8.6 to west

Explanation:

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If two people standing on a scooter board push off of each other what happens ( Newton’s 3rd law )
Keith_Richards [23]

Answer:They will go off in opposite directions with the same force.

Explanation:

Newton's Third Law states that for every action, there is an equal but opposite reaction. If two people are standing on a scooter and push off each other (following the Law), it should come to the conclusion that they could go off in opposite with the same force.

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What is the net force for this? (please don't forget it's direction and magnitude)​
avanturin [10]

Answer:

Explanation:

As the sum of the two right directed forces match exactly the left directed force, the only unbalanced force, and thus the net force, is the upward 25 N force.

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3 years ago
If the speed of a ball increased from 1m/s to 4m/s, by how much would the kinetic energy increase
GREYUIT [131]
In 16 times
KE= o.5 m times V squared
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3 years ago
A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t
user100 [1]

Answer:

the mass of water is 0.3 Kg

Explanation:

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since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) =  m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

m w= 1.80 kg *  0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))

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7 0
3 years ago
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Len [333]

Answer:

Explanation:

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acceleration a = 5.1 x 10¹⁵ m /s²

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