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Paraphin [41]
2 years ago
11

-2

Physics
1 answer:
photoshop1234 [79]2 years ago
7 0

Answer:-2

Explanation:

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If a 100-N net force acts on a 50-kg car, what will the acceleration of the car be?
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Newton's 2nd law of motion: 

                             Force = (mass) x (acceleration)

Divide each side by (mass):     

                             Acceleration = (force) / (mass)

                                               =  (100 N) / (50 kg)

                                               =  2 m/s²  


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A wave With wavelength 20 m has a frequency of 12 Hz what is the waves speed
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240m/s

Explanation:

The equation to calculate is wavelength= velocity/ frequency so to find the velocity you would have to multiply frequency by wavelength.

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What could you add to a closed circuit consisting of 2 batteries, 2 light bulbs, and a switch to Increase the current?
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The following that could be used to make the simplest circuit are a battery, wire, switch, and a light bulb. The answer is letter D. The battery provides the energy for the bulb to work. The wire provides a pathway for the electrons to move. The switch provides the open and close of the circuit.

Explanation:

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What is a point value for an arrow that is on two different colors?
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8 0
3 years ago
Ball A 1.55kg moving right at 8.76 m/s makes a head-on collision with ball B (0.752 kg) moving left at 11.4 m/s. After, ball B m
Illusion [34]

1.15 m/s to the left (3 sig. fig.).

<h3>Explanation</h3>

Momentum is conserved between the two balls if they are not in contact with any other object. In other words,

p_{\text{A,initial}} + p_{\text{B,initial}}=p_{\text{A,final}} + p_{\text{B,final}}

m_\text{A} \cdot v_{\text{A,initial}} + m_\text{B}\cdot v_{\text{B,initial}}=m_\text{A}\cdot v_{\text{A,final}} + m_\text{B}\cdot v_{\text{B,final}}, where

  • m stands for mass and
  • v stands for velocity, which can take negative values.

Let the velocity of objects moving to the right be positive.

  • m_\text{A} = 1.55\;\text{kg},
  • m_\text{B} = 0.752\;\text{kg}.

Before the two balls collide:

  • v_\text{A} = +8.76\;\text{m}\cdot\text{s}^{-1},
  • v_\text{B} = -11.4\;\text{m}\cdot\text{s}^{-1}.

After the two balls collide:

  • v_\text{A} needs to be found,
  • v_\text{B} = +9.03\;\text{m}\cdot\text{s}^{-1}.

Again,

m_\text{A} \cdot v_{\text{A,initial}} + m_\text{B}\cdot v_{\text{B,initial}}=m_\text{A}\cdot v_{\text{A,final}} + m_\text{B}\cdot v_{\text{B,final}},

1.55 \times (+8.76) + 0.752 \times (-11.4) = 1.55\;{\bf v_{\textbf{A,final}}} + 0.752 \times (+9.03).

v_{\text{A,final}} = \dfrac{1.55 \times (+8.76) + 0.752 \times (-11.4)-0.752 \times (+9.03)}{1.55} = -1.15\;\text{m}\cdot\text{s}^{-1}.

v_{\text{A,final}} is negative? Don't panic. Recall that velocities to the right is considered positive. Accordingly, negative velocities are directed to the left.

Hence, ball A will be travelling to the left at 1.15 m/s (3 sig. fig. as in the question) after the collision.

8 0
3 years ago
Read 2 more answers
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