A 15.75-g<span> piece of iron absorbs 1086.75 </span>joules<span> of </span>heat<span> energy, and its ... </span>How many joules<span> of </span>heat<span> are </span>needed<span> to raise the temperature of 10.0 </span>g<span> of </span>aluminum<span> from 22°C to 55°C, if the specific </span>heat<span> of </span>aluminum<span> is o.90 J/</span>g<span>”C2 .</span>
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Answer:
The solution and the graph are in the attached files below
Explanation:
Explanation:
By the statement, Efficiency of a machine is 60% it is meant that 'The work output is 60% of the work input'. If you apply 100J of energy for a machine, it will be able to life load of 60 J only
FORMULA:
- V = IR, where V = P.D; I = Current; R = Resistance.
ANSWER:
Total equivalent resistance for circuit:
R(eq) = R1 + R2 [It is in series]
Now, Current passing through whole circuit:
I = V/R
We know that, In series combination current passing through whole circuit is same.
So, V¹ = IR¹
V¹ = 1/50 × 330
And V² = IR²
V² = 1/50 × 470