Question

An object accelerates uniformly from 3.0 meters per second east to 8.0 meters per second east in 2.0 seconds. What is the magnitude of the acceleration of the object ?

Answer 1

Answer:

2.5 $ms^-^2$

Explanation:

As we can see in the question that initial and final directions of the velocity of the object are same i.e. east, so it is clear that object is in a straight line motion.

Given that,

Initial velocity of the object = 3 m/s

Final velocity of the object = 8 m/s

Time interval = 2 seconds

The following equation of motion in straight line can be used -

$v=u+at$

And thus acceleration can be calculated as

$a=\frac{v-u}{t}$ where, $v$ is final velocity and $u$ is initial velocity.

So, $a= \frac{8-3}{2} = 2.5 ms^-^2$