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grandymaker [24]

3 years ago

11

Eddie is reading a novel for English class. Has been read 173 out of 480 pages about what percent of the book has he read

1 answer:

pickupchik [31]3 years ago

6 0

12 .k4 an wi wow wi aisiwiw sneeze eehuwwkwkwjwueieuehehehehrhrhrhrhrhrhruhrrhhrhrrhhrhheehhdhdhrhrrhyrueueueueururuueyftfxyfccygcghr

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HELP WITH THESE QUESTIONS PART 2.

polet [3.4K]

Answer: (a) IV (b) positive (c) $\frac{\pi}{4}$ (d) C (e) $\sqrt{2}$

<u>Step-by-step explanation:</u>

a) $\frac{15\pi}{4}$ - $\frac{8\pi}{4}$ = $\frac{7\pi}{4}$ , which is located in Quadrant IV <em>per the Unit Circle. </em>

b) sec is $\frac{1}{cos}$ . Cos is the x-coordinate. The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from $\frac{7\pi}{4}$ to 2π = $\frac{\pi}{4}$

d) since the angle is below the x-axis and the reference angle is $\frac{\pi}{4}$ , then the angle is equal to $-sec(\frac{\pi}{4}$ )

e) sec = $\frac{1}{cos}$ ⇒ sec $\frac{7\pi}{4}$ = $\frac{2}{\sqrt{2} }$ = $\frac{2}{\sqrt{2} }$ $(\frac{\sqrt{2}} {\sqrt{2}})$ = $\frac{2\sqrt{2} }{2}$ = $\sqrt{2}$

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Answer: (a) $\frac{3\pi}{2}$ (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) $\frac{11\pi}{2}$ - $\frac{4\pi}{2}$ = $\frac{7\pi}{2}$ - $\frac{11\pi}{2}$ = $\frac{3\pi}{2}$

b) $\frac{3\pi}{2}$ is on the Unit Circle at (0, -1)

c) sin = $\frac{opposite}{hypotenuse}$ which equals $\frac{y}{r}$ on the Unit Circle.

d) sin is the y-coordinate. sin $(\frac{3\pi}{2})$ = -1

6 0

4 years ago

What is the distance between point A and B , to the nearest tenth ?

kondaur [170]

I can’t see where they are

6 0

3 years ago

Arlene Frank is saving money for her college

lora16 [44]

Can you please include a question please? Thank you

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME<br> MATH IS HARD

nata0808 [166]

Answer:

C

Step-by-step explanation:

You have to add the whole equation not only a part of it.

3 0

3 years ago

Read 2 more answers

Hey guys plz help meee<br><br>the answers have to be in numbers.

Licemer1 [7]

Answer:

$\overrightarrow{AB}=\frac{-9}{-4}$

$\overrightarrow{CD}=\frac{-5}{4}$

Step-by-step explanation:

A vector quantity is represented by $(\frac{y}{x})$

where y = y-coordinate and x = x-coordinate

Since vector AB represents a vector in 3rd quadrant,

It starts from point A and ends at B,

Therefore, coordinates of B are (-9, -4)

$\overrightarrow{AB}$ = $(\frac{-9}{-4})$

Similarly vector CD starts with C and ends at D in the 2nd quadrant,

Therefore coordinates of D will be (-5, 4)

$\overrightarrow{CD}=\frac{-5}{4}$

7 0

4 years ago