Ask question

Ask question

All categories

OverLord2011 [107]

3 years ago

9

Based on the image, determine the formula for a compound formed between lithium and sulfur. A) Li2S B) Li3S C) LiS D) LiS2

1 answer:

VashaNatasha [74]3 years ago

5 0

Answer: A

Explanation:

I got it right just wanted to have a letter answer for my fellow USA TestPrep people

You might be interested in

In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin

GuDViN [60]

Answer:

The velocity is $v_b = 20.17 \ m/s$

Explanation:

From the question we are told that

The mass of the ball is $m = 0.245 \ kg$

The radius is $r = 59.8 \ cm = 0.598 \ m$

The force is $F = 30.9 \ N$

The speed of the ball is $v = 16.0 \ m/s.$

Generally the kinetic energy at the top of the circle is mathematically represented as

$K_t = \frac{1}{2} * m * v^2$

=> $K_t = \frac{1}{2} * 0.245 * 16.0 ^2$

=> $K_t = 31.36 \ J$

Generally the work done by the force applied on the ball from the top to the bottom is mathematically represented as

$W = F * d$

Here d is the length of a semi - circular arc which is mathematically represented as

$d = \pi * r$

So

$W = 30.9 * 0.598$

$W = 18.48 \ J$

Generally the kinetic energy at the bottom is mathematically represented as

$K_b = \frac{1}{2} * m * v_b^2$

=> $K_b = \frac{1}{2} * 0.245 * v_b^2$

=> $K_b = 0.1225 * v_b^2$

From the law of energy conservation

$K_t + W =K_b$

=> $31.36+ 18.48 = 0.1225 * v_b^2$

=> $v_b = 20.17 \ m/s$

3 0

3 years ago

This proportion can be changed to (0.45)y = x, where x represents the person's weight in kilograms and y represents the person's

erica [24]

If .45y = 65
Then solving for y would give you: <span>y = 144</span>

7 0

3 years ago

Will give the first answer brainliest. Picture attached.

mylen [45]

Answer:

2699.73661Ω or 2.697kΩ

Explanation:

$V=IR$

So...

$R=\frac{V}{I}$

So...

$\frac{12.3}{0.004556} = 2699.73661$ Ω

This is the answer, but the resistance is much too high for a circuit like this

4 0

3 years ago

What is a crumple zone????

aksik [14]

A part of a motor vehicle

3 0

3 years ago

Read 2 more answers

A 30.0-g object connected to a spring with a force constant of 40.0 N/m oscillates with an amplitude of 6.00 cm on a frictionles

Naddika [18.5K]

Answer:

a) 72mJ

b) 0.33m/s

c) 54mJ

d) 18mJ

Explanation:

(a) The total energy of the system is given by:

$E_T=\frac{1}{2}kA^2$

where k is the force constant and A is the amplitude. By replacing we get:

$E_T=\frac{1}{2}(40N/m)(0.06m)^2=0.072J$ = 72mJ

(b) we can get the speed by the conservation of energy (the kinetic energy and potential energy must equal the total energy in any place):

$E_T=E_k+E_p\\\\\frac{1}{2}kA^2=\frac{1}{2}mv^2+\frac{1}{2}kx^2\\\\v=\sqrt{\frac{kA^2-kx^2}{m}}=\sqrt{\frac{(40N/m)((0.06m)^2-(0.0115m)^2)}{0.03kg}}=0.33m/s$

where we have used that x=1.15cm=0.0115m; A=6.00cm=0.06m

(c) Again, by the conservation of energy:

$E_k=\frac{1}{2}k(A^2-x^2)=\frac{1}{2}(40N/m)((0.06m)^2-(0.03m)^2)=0.054J=54mJ$

(d) $E_p=\frac{1}{2}kx^2=\frac{1}{2}(40.0N/m)(0.03m)^2=0.018J=18mJ$

hope this helps!!

6 0

3 years ago