Ask question

Ask question

All categories

2 years ago

8

When is there the least amount of heat transfer within a liquid

2 answers:

Annette [7]2 years ago

6 0

In the beginning, the melting stage they call it.

kap26 [50]2 years ago

5 0

Answer:When the temperature of the liquid is the same throughout

Explanation:

You might be interested in

The model of the universe that suggests that the sun is the center of the universe was first brought by

lakkis [162]

It is D,Copernicus.when he first proposed the idea everyone thought he was nuts and that it was not plausible.even though his theory wasn't so accurate it still helped further scientific research.HE was born February 19,1473 and he published a book about his theory.

4 0

3 years ago

Read 2 more answers

20 POINTS!!!! WILL MARK BRAINLIEST!!!!!

oee [108]

1. Because of gravity....

2. No you either feel still ( gravity) or is actually in movement....

please vote my answer branliest! Thanks

8 0

3 years ago

Read 2 more answers

Two farmers are trying to move a large rock that sits in a field. They use a long stick as a lever and a brick as the fulcrum, a

kumpel [21]

D is the answer for usatestprep

4 0

3 years ago

Read 2 more answers

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is

Scilla [17]

Answer:

The magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

Explanation:

Given that,

Angular velocity, $\omega_i=968.7\ rad/s$

The disk comes to rest, $\omega_i=0$

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

$\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2$

So, the magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

5 0

2 years ago

Two long straight parallel wires are separated by 7.0cm. There is a 2.0A current flowing in the first wire. If the magnetic fiel

aliina [53]

Answer:

The current in the second wire is 4.4 A.

Explanation:

Given that,

Distance =7.0 cm

Current in first wire = 2.0 A

The magnetic field strength is zero at distance of 2.2 cm from the first wire.

We need to calculate the current in the second wire

Using formula of magnetic field

$B=B_{1}-B_{2}$

$0=\dfrac{\mu_{0}I_{1}}{2\pi r_{1}}-\dfrac{\mu_{0}I_{2}}{2\pi r_{2}}$

$\dfrac{\mu_{0}I_{1}}{2\pi r_{1}}=\dfrac{\mu_{0}I_{2}}{2\pi r_{2}}$

$\dfrac{I_{1}}{r_{1}}=\dfrac{I_{2}}{(d-r_{1})}$

Here, $r_{2}=d-r_{1}$

$I_{2}=\dfrac{I_{1}\times(d-r_{1})}{r_{1}}$

Put the value into the formula

$I_{2}=\dfrac{2.0\times(7.0-2.2)}{2.2}$

$I_{2}=4.4\ A$

Hence, The current in the second wire is 4.4 A.

4 0

3 years ago