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3 years ago

How does the mass of and distance between the Sun and the Earth impact the number of days in a year?

Physics

1 answer:

Alexxandr [17]3 years ago

6 0

Answer:

Force of sun on earth can be written:

F = G M m / R^2

Centripetal force on earth can be written:

F= m w^2 R

Equating these:

G M / R^2 = w^2 R

Or w^2 = G (M / R^3)

Since no/ days per year is proportional to w (time for 1 revolution)

Increasing M (mass of sun) would increase w or decrease length of year

Increasing the mean radius R would decrease w or increase length of year

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Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their

Anna35 [415]

Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v= $\frac{s}{t}$
we get
V₁= $\frac{100}{10}$
V₁=10m/s

V₂= $\frac{100}{10.2}$
V₂=9.8m/s

V₃= $\frac{100}{10.4}$
V₃=9.61 m/s

V₄= $\frac{100}{10.6}$
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43

8 0

3 years ago

An example of when total internal reflection occurs is when all the light passing from a region of higher index of refraction to

Amiraneli [1.4K]

Answer:

is reflected back into the region of higher index

Explanation:

Total internal reflection is a phenomenon that occurs when all the light passing from a region of higher index of refraction to a region of lower index is reflected back into the region of higher index.

According to Snell's law, refraction of ligth is described by the equation

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

n1 is the refractive index of the first medium

n2 is the refractive index of the second medium

$\theta_1$ is the angle of incidence (in the first medium)

$\theta_2$ is the angle of refraction (in the second medium)

Let's now consider a situation in which

$n_1 > n_2$

so light is moving from a medium with higher index to a medium with lower index. We can re-write the equation as

$sin \theta_2 = \frac{n_1}{n_2}sin \theta_1$

Where $\frac{n_1}{n_2}$ is a number greater than 1. This means that above a certain value of the angle of incidence $\theta_1$ , the term on the right can become greater than 1. So this would mean

$sin \theta_2 > 1$

But this is not possible (the sine cannot be larger than 1), so no refraction occurs in this case, and all the light is reflected back into the initial medium (total internal reflection). The value of the angle of incidence above which this phenomen occurs is called critical angle, and it is given by

$\theta_c =sin^{-1}(\frac{n_2}{n_1})$