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bezimeni [28]
3 years ago
8

How does the mass of and distance between the Sun and the Earth impact the number of days in a year?

Physics
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

Force of sun on  earth can  be written:

F = G M m / R^2

Centripetal force on earth can be written:

F= m w^2 R

Equating these:

G M / R^2 = w^2 R

Or   w^2 = G (M / R^3)

Since no/ days per year is proportional to w (time for 1 revolution)

Increasing M (mass of sun) would increase w or decrease length of year

Increasing the mean radius R would decrease w  or increase length of year

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Name two physical properties that characterize matter
STatiana [176]

Answer:

Matter have two essential types of properties, those are physical properties and chemical properties.

Explanation:

8 0
4 years ago
Why are the largest craters we find on the Moon and Mercury so much larger than the largest craters we find on the Earth
Veronika [31]

Answer:

Because Moon and Mars has no atmosphere.

Explanation:

Moon and Mars has no atmosphere, so there is no friction on the falling object due to the atmosphere. The speed of the falling object is more at Moon and Mars.

When a small object impact on the surface of moon or Mars with high speed, the size of crater is large than the earth as out earth has atmosphere.

3 0
3 years ago
Your friend comes across a good deal to purchase a gold ring. She asks you for advice and for you to test the ring. The ring has
Luden [163]

Answer:

She is not getting a good deal.

Explanation:

The equation that relates heat with mass, specific heat and temperature change of an object is Q=mc\Delta T.

Always convert temperature to Kelvin, although in our case it's not necessary because the \Delta T will be the same, and we will leave the mass in grams because we will be getting J/g^{\circ}C units for specific heat, which we can compare to the one given for gold.

We then calculate the specific heat of the object in question:

c=\frac{Q}{m\Delta T}=\frac{94.8J}{(4.54g)(47.5^{\circ}C-23^{\circ}C)}=0.8523 J/g^{\circ}C

Which shows it's not gold.

5 0
3 years ago
A box of mass 50 kg is pushed hard enough to set it in motion across a flat surface. Then a 99-N pushing force is needed to keep
salantis [7]
The box is kept in motion at constant velocity by a force of F=99 N. Constant velocity means there is no acceleration, so the resultant of the forces acting on the box is zero. Apart from the force F pushing the box, there is only another force acting on it in the horizontal direction: the frictional force F_f which acts in the opposite direction of the motion, so in the opposite direction of F.
Therefore, since the resultant of the two forces must be zero,
F-F_f=0
so
F=F_f

The frictional force can be rewritten as
F_f = \mu m g
where m=50 kg, g=9.81 m/s^2. Re-arranging, we can solve this equation to find \mu, the coefficient of dynamic friction:
\mu =  \frac{F}{mg}= \frac{99 N}{(50 kg)(9.81 m/s^2)}  =0.20
4 0
3 years ago
What kind of acceleration occurs when an object speeds up? positive negative neutral zero
jarptica [38.1K]

Answer:

POSITIVE

Explanation:

The acceleration of an object is given by the rate of change of velocity.

u and v are initial and final velocities

If the final velocity is more than that of the initial velocity, the acceleration of the object is positive. It means positive acceleration occurs when an object speeds up. Hence, the correct option is (a) "positive".

5 0
3 years ago
Read 2 more answers
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