Answer:
4462.0927 W
Explanation:
= Emissivity of the panel = 1
= Stefan-Boltzmann constant = 
T = Temperature = (273.15+6)
Area of the panel is given by
The power radiated is given by
The power radiated from each panel is 4462.0927 W
Answer:
10.4 m/s
Explanation:
First, find the time it takes for the projectile to fall 6 m.
Given:
y₀ = 6 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: t
y = y₀ + v₀ t + ½ at²
(0 m) = (6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 1.11 s
Now find the horizontal position of the target after that time:
Given:
x₀ = 6 m
v₀ = 5 m/s
a = 0 m/s²
t = 1.11 s
Find: x
x = x₀ + v₀ t + ½ at²
x = (6 m) + (5 m/s) (1.11 s) + ½ (0 m/s²) (1.11 s)²
x = 11.5 m
Finally, find the launch velocity needed to travel that distance in that time.
Given:
x₀ = 0 m
x = 11.5 m
t = 1.11 s
a = 0 m/s²
Find: v₀
(11.5 m) = (0 m) + v₀ (1.11 s) + ½ (0 m/s²) (1.11 s)²
v₀ = 10.4 m/s
Answer:
People might misunderstand it and problems might happen because the audience will have different opinions.
Explanation:
Answer:
Power = 1625 Watts
Explanation:
Given the following data;
Energy = 65,000 J
Time = 40secs
To find the power;
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
Substituting into the equation, we have
Power = 65,000/40
Power = 1625 Watts
