2 years ago

What two factors determine the amount of friction there will be between objects?

Physics

1 answer:

barxatty [35]2 years ago

6 0

Answer:

the two factors are the mass of the objects and the coefficient of friction between them

Explanation:

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Which of the following has the least resistance? wood iron copper silver

Neporo4naja [7]

Answer:

Probably wood

Explanation:

6 0

3 years ago

A typical laboratory centrifuge rotates at 3700 rpm . Test tubes have to be placed into a centrifuge very carefully because of t

Alexus [3.1K]

Answer:

Explanation:

acceleration of test tube

= ω² R

= (2πn)² R

= 4π²n²R

n = no of rotation per second

= 3700 / 60

= 61.67

R = .10 m

acceleration

= 4π²n²R

= 4 x 3.14² x 61.67² x .10

= 14999 N Approx

3 0

3 years ago

What does it mean to have an acceleration of -10 m/s^2 when the velocity is 80 m/s?

mamaluj [8]

Answer:

1,3

Explanation:

As the acceleration is -10m/s^2 , that means deceleration is occurring. That means, the object is slowing down.

v=u-at

or, 0=80-10t

or, t=8 seconds

So, the object will stop in 8 seconds.

So, the correct answers are 1 and 3.

Hope, this helps you.

3 0

2 years ago

A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 3 kilograms is tied to the middle of the cloth

Alla [95]

Answer:

The magnitude of the tension on the ends of the clothesline is 41.85 N.

Explanation:

Given that,

Poles = 2

Distance = 16 m

Mass = 3 kg

Sags distance = 3 m

We need to calculate the angle made with vertical by mass

Using formula of angle

$\tan\theta=\dfrac{8}{3}$

$\thta=\tan^{-1}\dfrac{8}{3}$

$\theta=69.44^{\circ}$

We need to calculate the magnitude of the tension on the ends of the clothesline

Using formula of tension

$mg=2T\cos\theta$

Put the value into the formula

$3\times9.8=2T\times\cos69.44$

$T=\dfrac{3\times9.8}{2\times\cos69.44}$

$T=41.85\ N$

Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.

4 0

3 years ago

Read 2 more answers

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VMariaS [17]

Answer:

a.proton, proton

hope this helped :) have a goodday

6 0

3 years ago