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Lelechka [254]
3 years ago
10

with respect to air the refractive index of ice is 1.31 and that of rock salt is 1.54 calculate the refractive index of rock sal

t with respect to ice​
Physics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:

1.17

Explanation:

Given that,

The refractive index of ice wrt air = 1.31

The refractive index of rock salt wrt air = 1.54

We need to find the refractive index of rock salt with respect to ice.

We know that,

refractive index = (speed of light in air or vaccum)/( speed of light in that medium)

So,

The speed of light in ice = c/(1.31)

The speed of light in rock salt = c/(1.54)

So, the refractive index of rock salt with respect to ice​ is :

\mu=\dfrac{1.54}{1.31}\\\\=1.17

So, the required refractive index of rock salt wrt ice is 1.17.

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Where is the center of mass of the Earth-Moon system? The radius of the Earth is 6378 km and the radius of the Moon is 1737 km.
lions [1.4K]

Answer:

r_{cm} = 4.67 10⁶ m

We see that none of the answers is correct, the closest is the third, but the center of mass is within the radius of the Earth

Explanation:

The definition of the center of mass is

      r_{cm} = 1 / M ∑r_{i}  m_{i}

Where M is the total mass, r_{i} and m_{i}mi are the position and the mass gives each of the bodies

We must locate a reference system for the calculation, we will locate it with the origin in the center of the Earth, the data we have are

Mass of the Earth Me = 5.98 1024 kg

Moon mass m = 7.36 1022 kg

Earth to Moon Distance r = 3.84 108 m

Let's apply this to our case

      r_{cm} = 1 / (Me + m) (Me 0 + m R)

      r_{cm} = 1 / (598 +7.36) 10²² (0 + 7.36 10²² 3.84 10⁸)

     r_{cm} = 4.67 10⁶ m

We can see that this distance is less than the radius of the Earth

We see that none of the answers is correct, the closest is the third, but the center of mass is within the radius of the Earth

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What does the term "catastrophic event" mean to you
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A projectile is launched at ground level with an initial speed of 50.0m/s at an angle of 30° above the horizontal. It strikes a
tino4ka555 [31]

Answer:

x = 129.9 m

y = 30.9 m

Explanation:

When an object is thrown into the air under the effect of the gravitational force, the movement of the projectile is observed. Then it can be considered as two separate motions, horizontal motion and vertical motion. Both motions are different, so that they can be handled independently.

Given data:

v_{i} = 50 m/s

Angle = 30°

Time = t = 3 s

horizontal component of velocity = v_{i_{x}} = v_{i}cos30°

v_{i_{x}} = 50cos30°

v_{i_{x}} = 43.3 m/s

Vertical component of velocity = v_{i_{y}} = v_{i}Sin30°

v_{i_{y}} = 50Sin30°

v_{i_{y}} = 25 m/s

This is a projectile motion, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.

But the vertical component of velocity varies with time and there is an acceleration along vertical direction which is equal to gravitational acceleration g.

Horizontal distance = x =  v_{i_{x}}t

x =  43.3*3

x = 129.9 m

Vertical Distance = y = v_{i_{y}}t -0.5gt²

y = 25*3 - 0.5*9.8*3²

y = 75 - 44.1

y = 30.9 m

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3 years ago
A 1400-kg car is moving at a speed of 25m/s. how much kinetic energy does the car have?
Luba_88 [7]

Answer:

437.5Kjoules

Explanation:

K.E=half multiply by mass multiply by square of velocity

=437.5Kjoules

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3 years ago
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