Answer:
Cost of silk was too high
Explanation:
The major reason of not using silk as a fabric in the hot air balloons was high cost of silk. Due to its high cost, silk became unaffordable for use in modern balloon.
If cost is neglected, then silk is the perfect material for hot air balloon as it is light in weight
Answer:
3.97× 10²³ atoms of Ag
Explanation:
Given data:
Mass of Ni = 112 g
Mass of AgNO₃ = 112 g
Atoms of silver produced = ?
Solution:
Chemical equation:
Ni + 2AgNO₃ → 2Ag + Ni(NO₃)₂
Number of moles of Ni:
Number of moles = mass/ molar mass
Number of moles = 112 g/58.7 g/mol
Number of moles = 2 mol
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 112 g/169.87 g/mol
Number of moles = 0.66 mol
Now we will compare the moles of Ag with both reactants.
AgNO₃ : Ag
2 : 2
0.66 : 0.66
Ni : Ag
1 : 2
2 ; 2×2= 4 mol
Number of moles of Ag produce by AgNO₃ are less so it will limiting reactant and limit the yield of Ag.
I mole = 6.022 × 10²³ atoms
0.66 mol × 6.022 × 10²³ atoms / 1 mol
3.97× 10²³ atoms of Ag
Elements are substances that are made up of the same atoms which are capable of taking part in a chemical reaction.
There are different types of elements which are represented by symbols gotten from the first letter or the first and any other letter in the name of the element.
Examples of elements include:
When two or more of these elements combine together through a chemical bond, it leads to the formation of compounds.
Example of a compound includes:
- NaCl: The element sodium combine, through electrochemical bonding, with another element chlorine to form the compound sodium chloride.
Learn more here:
brainly.com/question/17571315
Answer : The new volume of was, 5.17 L
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Therefore, the new volume of was, 5.17 L