A rubber ball is dropped and bounces vertically from a horizontal concrete floor. If the ball has a speed of 4.1 m/s just before
1 answer:
To solve this problem it is necessary to apply Newton's second law with the peculiarity that the expression given for velocity must be expressed in terms of the rate of change of velocity and time.
Mathematically this is,
F= ma
Where,
m = mass
= Change in velocity
t = Time
Since the time interval occurs when the speed hits - in the downward direction - until it bounces - in the upward direction - we will have that the change in speed is given by
The rest of our values are given as:
m = 0.26s
t = 0.44kg
Finally replacing we will have to
Therefore the final average force of the floor on the ball is 13.53N
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Answer:
0.003181 radians
0.003005 radians
Explanation:
Number of slits = 140 /cm
λ = Wavelength = 434 nm = 434×10⁻⁹ m
m = 3 Third order spectrum
Space between slits
Now,
0.003181 radians
When λ = 410 nm = 410×10⁻⁹ m
0.003005 radians
Answer: The velocity is the wave traveling at before the transmitter converts it to a sound wave is
Explanation:
Wavelength of the electromagnetic wave = 23,076 m
Frequency of the wave = 13,000 Hertz
The velocity is the wave traveling at before the transmitter converts it to a sound wave is