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Blababa [14]
3 years ago
13

(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST IF YOU'RE ANSWER IS CORRECT! AND MAYBE EXTRA POINTS!)

Chemistry
2 answers:
ozzi3 years ago
4 0
Best guess
Answer: c
Paraphin [41]3 years ago
4 0

Answer:

The answer is B. Add up readings from each sliding mass.

Hopes it helps!

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1. How is melting point of a solid determined?
Oxana [17]

Answer:

Melting points are often used to characterize organic and inorganic crystalline compounds and to ascertain their purity.

Explanation:

4 0
3 years ago
Write a chemical equation that shows the release of hydroxide ions as each of these bases dissolves in water.
Zarrin [17]
KOH -------> K+ OH-
Ba(OH)2 ------> Ba+2. 2OH-
5 0
3 years ago
Approximately how many particles are in 2 moles?
schepotkina [342]

Answer:

1.2\times10^2^4 particles in 2 moles.

Explanation:

The number of particles that are contained in one mole, the international unit of amount of substance: by definition, exactly 6.022×10²³, and it is dimensionless. It is named after the scientist Amedeo Avogadro.

It is also known as Avogadro's constant.

∴ Number of particles in one mole = 6.022\times10^2^3

∴ Number of particles in 2 mole = 2 times Number of particles in one mole

∴ Number of particles in 2 mole=2\times6.022\times10^2^3=12.044\times10^2^3\approx1.2\times10^2^4

Hence there are 1.2\times10^2^4 particles in 2 moles.

4 0
3 years ago
Read 2 more answers
If a container contains 3.5 moles and has a volume of 1.5 L, then what volume is it when it contains 8 moles? *
Lilit [14]
Volume would be 3.4 L
8 0
3 years ago
The vapor pressure of water at 25.0°C is 23.8 torr. Determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
mrs_skeptik [129]

According to Raoult's law the relative lowering of vapour pressure of a solution made by dissolving non volatile solute is equal to the mole fraction of the non volatile solute dissolved.

the relative lowering of vapour pressure is the ratio of lowering of vapour pressure and vapour pressure of pure solvent

\frac{p^{0-}p}{p^{0}}=x_{B}

Where

xB = mole fraction of solute=?

p^{0}=23.8torr

p = 22.8 torr

x_{B}=\frac{23.8-22.8}{23.8}=0.042

mole fraction is ratio of moles of solute and total moles of solute and solvent

moles of solvent = mass / molar mass = 500 /18 = 27.78 moles

putting the values

molefraction=\frac{molessolute}{molesolute+molessolvent}

0.042=\frac{molessolute}{27.78+molessolute}

1.167+0.042(molesolute)=molessolute

molessolute=1.218

mass of glucose = moles X molar mass = 1.218 X 180 = 219.24 grams



3 0
3 years ago
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