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3 years ago

PLEASE HELP ASAP!

Mathematics

1 answer:

Reil [10]3 years ago

4 0

Answer:

i think 125

Step-by-step explanation:

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I need to know, the area of sector AOB is what fractional part of the area of circle O

sertanlavr [38]

We are given that triangle AOB

6 0

1 year ago

The perimeter of a playing field for a certain sport is 334ft. The field is a rectangle, and the length is 47 ft longer than the

babunello [35]

Answer:

The dimensions of the rectangle = 60ft by 107ft

Where 60 ft = Width of the playing field

107ft = Length of the playing field

Step-by-step explanation:

A playing field is Rectangular is shape, hence,

The formula for Perimeter of a rectangle = 2(L + W)

P = 334 ft

L = 47 + W

W = W

Hence we input these values in the formula and we have:

334 = 2(47 + W + W)

334 = 2(47 + 2W)

334 = 94 + 4W

334 - 94 = 4W

240 = 4W

W = 240/4

W = 60

There fore, the width of this playing field = 60 ft

The length of this rectangle is calculated as:

47 + W

47 + 60

= 107 ft

The length of this playing field = 107ft

Therefore the dimensions of the rectangle = 60ft by 107ft

6 0

3 years ago

Show that 5^133 +26 is a multiple of 31

MArishka [77]

Answer:

3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the probability that a marble chosen at random is

Brums [2.3K]

Answer:

$P=\frac{6}{11}$

Step-by-step explanation:

The probability can be defined as the ratio between the possible events and the total number of outcomes.

In this case, according to the image attached, the total number of outcomes is 11, because they are 11 marbles in total.

Now, the specific event is all shaded marbles or labeled with a multiple of 3. With this specific characteristics 6 marbles, because there are 5 shaded marbles and 6 is a multiple of 3. So, the possible events are 6.

Therefore, the probability is

$P=\frac{6}{11}$

The right answer is the last choice.

4 0

4 years ago

Read 2 more answers

What is the approximate area of a circle with a radius of 10 in?

yKpoI14uk [10]

$\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}$

Correction to your question text: diameter, not radius.

The area of a circle is given by:

$A=\pi r^2$

The radius is half of the diameter.

$A=\pi\cdot\left(\dfrac{10}{2}\right)^2$

Substitute and solve.

$\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}$

5 0

2 years ago