Answer:
10.8
Step-by-step explanation:
To find (f/g)(5), find f(5) and (g5) then divide the values.
f(5) = 7 + 4(5) = 27
g(5) = 1/2 (5) = 2.5
27/2.5 = 10.8
Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
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As h approaches 0 from the positive side, then:
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Thus, f'(c) = 0
The answer is 145 mansnjsjejsjjsjsjejejejejejejdjuehdybe
Answer:
yupyup
Step-by-step explanation:
been having it for years now