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tia_tia [17]
4 years ago
12

If the neutron microscopic absorption cross section of boron at 0.0253 eV is 3847 barns, what would it be at 0.1 eV? [ Ans. 1935

b ]
Physics
1 answer:
Bingel [31]4 years ago
8 0

Answer:

The correct answer will be "1935 barns".

Explanation:

The given values are:

E_{1} = 0.0253 eV

E_{2} = 0.1 eV

\sigma_{2} = 3847 barns

Now,

⇒  \frac{\sigma_{1}}{\sigma_{2}} = \frac{E_{1}}{E_{2}}

then,

⇒  \sigma_{1}=\sigma_{2}\sqrt{\frac{E_{1}}{E_{2}}

On substituting the given values, we get

⇒       =3847\times \sqrt{\frac{0.0253}{0.1} }

⇒       =1935 \ barns

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