Question

A window in a submersible needs to be able to withstand the incredible forces that water will exert at depth. If the window is 30 cm x 15 cm, what would the force exerted by the water be at a depth of 1 km

Answer 1

Answer:

Explanation:

Area of the window, A = 30 cm x 15 cm = 0.045 m²

depth, h = 1 km = 1000 m

Let P is the pressure

P = h x d x g

where d is the density of water

P = 1000 x 1000 x 9.8 = 9.8 x 10^6 Pa

Force, F = Pressure x Area

F = 9.8 x 10^6 x 0.045

F = 4.41 x 10^5 N

Answer 2

Answer:

$F=441000\ N$

Explanation:

Given:

dimension of the window, $(30\times 15)\ cm$

depth of window under water, $d=1000\ m$

We know that the pressure due to liquid column is given as:

$P=\rho.g.d$

where:

$\rho=$ density of water

$g=$ acceleration due to gravity

$d=$ depth of the water column at the desired position

$P=1000\times 9.8\times 1000$

$P=9800000\ Pa$

Now the force acting on the area of the window:

$F=P.A$

where:

$A=$ area of the window

$F=9800000\times (0.3\times 0.15)$

$F=441000\ N$