If velocity is positive, which woul

Three children are playing a game in the playground. They stand on the playground facing each other. They want to place a ball o

dalvyx [7]

Answer:

The midpoint

Explanation:

3 0

3 years ago

What current is taken by the lamp when it is connected to a 220 v mains supply? what is the resistance of the lamp

eimsori [14]

Answer:

Given parameters

Potential difference (V) = 220 V

Power of lamp 1 (P1) = 100 W

Power of lamp 2 (P2) = 60 W

Both the bulbs are connected in parallel. Therefore, the potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.

We know that

Power = Voltage x Current

P = V x I

I = P/V

Lamp 1:

I1 = P1/V

I1 = 100/220

I1 = 5/11 A

Lamp 2:

I2 = P2/V

I2 = 60/220

I2 = 3/11 A

Net current (I) = I1 + I2

I = 5/11 + 3/11

I = 8/11

I = 0.7273 A

Hence, current drawn from the line is 0.727 A

Explanation:

Hope this helps!

7 0

3 years ago

Which image shows the correct way of lining up vectors to add them together? A. two arrows lined up facing away from each anothe

Morgarella [4.7K]

The image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

<h3>What is a vector quantity?</h3>

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

Thus, the image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

Learn more about the vector quantity here , refer to the link given below ;

brainly.com/question/15516363

#SPJ1

8 0

1 year ago

"A parcel moving in a horizontal direction with speed v0 = 13 m/s breaks into two fragments of weights 1.4 N and 1.9 N, respecti

Lady bird [3.3K]

Answer:

the smaller particle moves with speed of 8.706 m/s in the opposite direction to the bigger particle.

Explanation:

Speed of the original particle = 13 m/s

We designate particles as A and B

The final weights of the component particles are

Particle A = 1.4 N

particle B = 1.9 N

The speed of the larger piece (particle B) = 29 m/s

We know that weight is the product of a body's mass and acceleration due to gravity g which is equal to 9.81 m/s^2, therefore, masses of the particles are

particle A = 1.4/9.81 = 0.143 kg

Particle B = 1.9/9.81 = 0.194 kg

The momentum of a body is the product of its mass and its velocity i.e

P = mv

This means that the mass of the particle before splitting is

0.143 kg + 0.194 kg = 0.337 kg

Momentum of the initial whole particle = mv

==> 0.337 x 13 = 4.381 kg-m/s

The bigger particle B remains horizontal, and has a momentum of

mv = 0.194 x 29 = 5.626 kg-m/s

According to the conservation of momentum, the total initial momentum of a system must be equal tot the total final momentum of the system.

Initial total momentum of the system = 4.381 kg-m/s (momentum of original particle before splitting)

Final total momentum of the system = Total momentum of the particles after splitting = 5.626 kg-m/s + ( 0.143 kg x $V_{B}$ )

where $V_{B}$ is the velocity of smaller particle A

final total momentum of the system = 5.626 + 0.143 $V_{B}$

Equating the two momenta of the system, we'll have

4.381 = 5.626 + 0.143 $V_{B}$

4.381 - 5.626 = 0.143 $V_{B}$

-1.245 = 0.143 $V_{B}$

$V_{B}$ = -1.245/0.143 = -8.706 m/s

The negative sign indicates that the smaller particle moves in the opposite direction to the bigger particle

5 0

3 years ago

A solid conducting sphere has net positive charge and radiusR = 0.600 m . At a point 1.20 m from the center of the sphere, the e

gayaneshka [121]

Answer:

V_inside = 36 V

Explanation:

Given

We are given a sphere with a positive charge q with radius R = 0.400 m Also, the potential due to this charge at distance r = 1.20 m is V = 24.0 V.

Required

We are asked to calculate the potential at the centre of the sphere

Solution

The potential energy due to the sphere is given by equation

V = (1/4*π*∈o) × (q/r) (1)

Where r is the distance where the potential is measured, it may be inside the sphere or outside the sphere. As shown by equation (1) the potential inversely proportional to the distance V

V ∝ 1/r

The potential at the centre of the sphere depends on the radius R where the potential is the same for the entire sphere. As the charge q is the same and the term (1/4*π*∈o) is constant we could express a relation between the states , e inside the sphere and outside the sphere as next

V_1/V_2=r_2/r_1

V_inside/V_outside = r/R

V_inside = (r/R)*V_outside (2)

Now we can plug our values for r, R and V_outside into equation (2) to get V_inside

V_inside = (1.2 m )/(0.600)*18

= 36 V

V_inside = 36 V

7 0

3 years ago

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