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jek_recluse [69]
3 years ago
11

What is the primary force that helps suspension bridges use cables to hold their spans up? A. tension force B. resistance force

C. normal force D. elastic force E. applied force
Physics
2 answers:
dlinn [17]3 years ago
7 0

Answer:

The correct answer is option A. "tension force".

Explanation:

Suspension bridges, like the Golden Gate Bridge or the Brooklyn Bridge, use tension force as the primary source of force that cables use to hold their spans up. The supporting cables receive the tension forces of the bridge, and this same force passes to the anchorages and into the ground. This equilibrium that the tension force gives among the different elements of the bridge, gives the support to hold the bridge together.

aleksandr82 [10.1K]3 years ago
5 0

Answer:

A. Tension force

Explanation:

These are bridges that use cables to hold the road way up.

The cables in a suspension bridge receive the tension force of the bridge. These cables transmit these forces to the towers supporting the bridge and are compressed into the ground.

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A particular balloon can be stretched to a maximum surface area of 1257 cm2. The balloon is filled with 3.1 L of helium gas at a
chubhunter [2.5K]

Answer:

The ballon will brust at

<em>Pmax = 518 Torr ≈ 0.687 Atm </em>

<em />

<em />

Explanation:

Hello!

To solve this problem we are going to use the ideal gass law

PV = nRT

Where n (number of moles) and R are constants (in the present case)

Therefore, we can relate to thermodynamic states with their respective pressure, volume and temperature.

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} --- (*)

Our initial state is:

P1 = 754 torr

V1 = 3.1 L

T1 = 294 K

If we consider the final state at which the ballon will explode, then:

P2 = Pmax

V2 = Vmax

T2 = 273 K

We also know that the maximum surface area is: 1257 cm^2

If we consider a spherical ballon, we can obtain the maximum radius:

R_{max} = \sqrt{\frac{A_{max}}{4 \pi}}

Rmax = 10.001 cm

Therefore, the max volume will be:

V_{max} = \frac{4}{3} \pi R_{max}^3

Vmax = 4 190.05 cm^3 = 4.19 L

Now, from (*)

P_{max} = P_1 \frac{V_1T_2}{V_2T_1}

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Pmax= P1 * (0.687)

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The following is not true about the Law of Conservation of Energy:

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