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zavuch27 [327]
3 years ago
13

A lawn roller in the form of a solid uniform cylinder is being pulled horizontally by a horizontal force B applied to an axle th

rough the center of the roller. The roller radius 0.59 m and mass 48 kg. What magnitude B of the force is required to produce and acceleration a=4.2 m/s^2 of the center of mass of the roller if the lawn rolls without slipping?

Physics
1 answer:
horsena [70]3 years ago
4 0

Answer:

Explanation:

mass, m = 48 kg

radius, r = 0.59 m

acceleration of center of mass, a = 4.2 m/s2

The free body diagram of cylinder is as follows:

Since the cylinder is rolling without slipping, therefore,a=αr,

which gives, angular acceleration, α = a/r = (4.2/0.59)rad/s2 = 7.12 rad/s2

Moment of inertia of cylinder about center of mass C, IC= (1/2)mr2

So, by parallel axis theorem, moment of inertia about point A,IA = (1/2)mr2 + mr2 =(3/2)mr2 = (3/2)*48*0.592 kg.m2 =25.06 kg.m2

Now, taking the moment of forces about point A, T =IAα

which gives, B*r = IAα, and we get, B =(25.06*7.12)/0.59 N = 302.42 N

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The net force on an object moving with constant speed in circular motion is in which direction
ipn [44]

Answer:

the net force is the same direction as the acceleration

Explanation:

so toward the center of the circle about which the object is constantly moving.

7 0
2 years ago
A train is moving in a straight railway where it covered one third of the distance with
Alexxandr [17]

Answer:

<em>The average speed of the train is 45 km/h</em>

Explanation:

<u>Speed</u>

It's defined as the distance (d) per unit of time (t) traveled by an object. The formula is:

\displaystyle v=\frac{d}{t}

Let's call x the total distance covered by the train. It covered d1=1/3x with a speed of v1=25 km/h. The time taken is calculated solving for t:

\displaystyle t_1=\frac{d_1}{v_1}

\displaystyle t_1=\frac{1/3x}{25}

\displaystyle t_1=\frac{x}{75}

Now the rest of the distance:

d2 = x - 1/3x = 2/3x

Was covered at v2=75 km/h. Thus the time taken is:

\displaystyle t_2=\frac{d_2}{v_2}

\displaystyle t_2=\frac{2/3x}{75}

\displaystyle t_2=\frac{2x}{225}

The total time is:

\displaystyle t_t=\frac{x}{75}+\frac{2x}{225}

\displaystyle t_t=\frac{3x}{225}+\frac{2x}{225}

\displaystyle t_t=\frac{5x}{225}

Simplifying:

\displaystyle t_t=\frac{x}{45}

The average speed is the total distance divided by the total time:

\displaystyle \bar v=\frac{x}{\frac{x}{45}}

Simplifying:

\boxed{\displaystyle \bar v=45\ km/h}

The average speed of the train is 45 km/h

5 0
3 years ago
If an insulator replaces a conductor in an electrical circuit, the flow of electrons in the circuit will be
Degger [83]
The flow of electrons in the circuit will be less.
6 0
3 years ago
What is an element that needs to lose or gain<br> 4 valence electrons in order to become<br> stable?
tiny-mole [99]

Answer:

Elements in Group 14 could lose four, or gain four electrons to achieve a noble gas structure. In fact, if they are going to form ions, Group 14 elements form positive ions. Carbon and silicon form covalent bonds. Carbon's millions of organic compounds are all based on shared electrons in covalent bonds.

Explanation:

4 0
3 years ago
a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?
Liono4ka [1.6K]

<u>Answer:</u>

The acceleration of the car is 3.13 m/s^2

<u>Explanation:</u>

In the question it is given that car initially heads north with a velocity 15 m/s. It then accelerates for 4.25 s and in the end its velocity is 28.3 m/s.

initial velocity u = 15 m/s

time t=4.25 s

final velocity v=28.3 m/s

The equation of acceleration is

a= \frac{(v-u)}{t}

= \frac{(28.3-15)}{4.25} =  \frac {13.3}{4.25} =3.13m/s^2

The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.

7 0
2 years ago
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