Answer:
<em>The speed of metal block B is 5 m/s after the collision</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of them all
If some collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses, we have:
The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.
After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':
Substituting the given values:
The speed of metal block B is 5 m/s after the collision
820.9 million km thats your answer
Complete Question
The complete question is shown in the first uploaded image
Answer:
a
When the both bulb are in the circuit bulb B glows equally brighter to bulb A
This because the power delivered to the both bulb are equal
b
The bulb A on the right will glow brighter than the bulb A on the left due to the fact that the power supplied to bulb A on the right is higher than that gotten by bulb A on the left.
Explanation:
From the question we are been told that the two bulbs are identical
So their resistance denoted by R is the same
Considering the left circuit where the two bulbs are connected in series which mean that the same current is passing through them
The power that is been deposited on the circuit is evaluated as
For the fact that the power deposited on the bulbs are the same they will glow equally
When B is now removed and only A is left
For the fact that its only bulb A that is on that right circuit the power delivered to it would be greater compared to the left circuit bulb A
Complete Question:
A child pushes horizontally on a box of mass m which moves with constant speed across a horizontal floor. The coefficient of friction between the box and floor is u. At what rate does the child do work on the box? g= gravity
A: umgv, mgv, v/umg, umg/v, umv^2 2.
Answer:
1. μ*m*g*v
Explanation:
As the box is moving at constant speed, in the horizontal plane, we have two forces present, that must be equal and opposite each other so the net horizontal force be zero: the force that the child does and the friction force.
⇒ Fc = Ff = μ*N (by definition of kinetic friction) (1)
Now, as the box is at rest regarding the vertical direction, the forces acting in this direction (gravity and the normal force) must be equal and opposite each other:
N = Fg = m*g
Replacing in (1) , we have:
Ff = μ*m*g
The work done by the child is as follows:
W = μ*m*g*d
The rate at which the work is done is just the power, which can be expressed as follows:
P = W/t = μ*m*g*(d/t)
but d/t = v (by definition), so we can write the following:
P= μ*m*g*v
Answer:Its empty car, small child, and then adult.
Explanation:
i took it
