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3 years ago

Which ordered pair is in the solution set of 0.5x – 2y > 3?

Mathematics

1 answer:

Sholpan [36]3 years ago

8 0

Answer:

See Below

Step-by-step explanation:

The left side of the equation HAS TO BE GREATER THAN 3

So we take each ordered pair (x,y), plug it into the expression of left side of inequality and see which one is GREATER THAN 3. That's our answer.

0.5x - 2y

0.5(-2) -2(0.5) = -2

0.5x - 2y

0.5(2) -2(1) = -1

0.5x -2y

0.5(2) -2(-1) = 3

0.5x -2y

0.5(-2) -2(-0.5) = 0

None of them are solutions. C would have been a solution if the inequality had an "EQUAL SIGN" -- but it doesn't. Maybe the question is wrong, but if the question is right, then there is no correct answer.

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What is the equation of the circle whose diameter has endpoints (8,-2) and (-2,6)?

klemol [59]

Answer:

$(x-3)^{2} +(y-2)^{2}=41$

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(8,-2)\\E(-2,6)$

substitute the values

$d=\sqrt{(6+2)^{2}+(-2-8)^{2}}$

$d=\sqrt{(8)^{2}+(-10)^{2}}$

$d=\sqrt{164}\ units$

$d=2\sqrt{41}\ units$

step 2

Find the center of the circle

The center is the midpoint of the diameter

The center is equal to

$C=(\frac{8-2}{2},\frac{-2+6}{2})$

$C=(3,2)$

step 3

Find the equation of the circle

The equation of the circle in center radius form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

we have

(h,k)=(3,2)

$r=2\sqrt{41}/2=\sqrt{41}\ units$ ---> the radius is half the diameter

substitute

$(x-3)^{2} +(y-2)^{2}=(\sqrt{41})^{2}$

$(x-3)^{2} +(y-2)^{2}=41$

4 0

4 years ago

Where does the money come from that is used to pay taxes?

Sladkaya [172]

Answer:

It comes from you :)

7 0

3 years ago

Read 2 more answers

Explain Well please.

Art [367]

The answer is C，
as she uses SSS to prove its congruent, she uses sides instead of angles so option a and d is not correct. as it needs to prove triangle pqr is congruent to triangle sqr, its not necessary to prove PQ is equal to QR. so the answer is c

7 0

3 years ago

If h(x)=4x^2-16 we’re shifted 7 units to the right and 3 units down what would the new equation be

attashe74 [19]

Answer:

4(x-7)^2 - 19

Step-by-step explanation:

Shifting 7 units to the right: 4(x-7)^2 - 16.

3 units down: 4(x-7)^2 - 16 - 3, or 4(x-7)^2 - 19

6 0

3 years ago

Multiply using a special product formula (6x-8) (6x+8)

ANEK [815]

The correct answer is B.

6x*6x=36x

-8*+8=-64

Thus, our equation is 36x-64

Hope this helps!

4 0

3 years ago