What is the effect on the gas’ pressure when compressing a gas to 1/3 of its volume? Explain
1 answer:
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Answer:
Temperature of the hot reservoir is 1540K
Explanation:
0.2=({T_c}+308-{T_c})/{T_c}+308
.2({T_c}+61.6=308
0.2{T_c}=246.4
{T_c}=1232
recall from equation 1
{T_h}=308+1232
{T_h}=1540K
Answer:
The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x N/C
Explanation:
given information,
kinetic energy, KE = 3.25 x J
proton's mass, m = 1.673 x kg
charge, q = 1.602 x C
distance, d = 2 m
to find the electric field that will stop the proton, we can use the following equation:
E = F/q
= (KE/d) / q , KE = Fd --> F = KE/d
= KE/qd
= (3.25 x J) / (1.602 x
C)(2 m)
= 1.01 x N/C