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Airida [17]
3 years ago
15

The plants shown bloom in summer. Which statement explains why the plants bloom in summer? The nights are shorter. The nights ar

e longer. The nights are colder. The nights are warmer.
Chemistry
1 answer:
Bess [88]3 years ago
5 0

Answer:

It’s A

Explanation:

The nights are shorter. I just took the unit test review

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What is the pH of a solution with [H+]=6.2x10-9 M?
Serga [27]

Answer: 8.2

Explanation:

pH of a solution is  - Log [ H+].

pH = - Log [ 6.2 x 10-9 M]

     = 9 - 0.7924

pH =  8.24 approx 8.2

3 0
2 years ago
A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
3 years ago
How many moles of \ce{Fe2O3}FeX 2 ​ OX 3 ​ will be produced from 27.0 \text{ g}27.0 g27, point, 0, start text, space, g, end tex
ira [324]

Answer : The number of moles of Fe_2O_3  produced will be, 0.241 moles.

Solution : Given,

Mass of Fe = 27.0 g

Molar mass of Fe = 56 g/mole

First we have to calculate the moles of Fe.

\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}=\frac{27.0g}{56g/mole}=0.482moles

Now we have to calculate the moles of Fe_2O_3

The balanced chemical reaction is,

4Fe+3O_2\rightarrow 2Fe_2O_3

From the reaction, we conclude that

As, 4 mole of Fe react to give 2 mole of Fe_2O_3

So, 0.482 moles of Fe react to give \frac{0.482}{4}\times 2=0.241 moles of Fe_2O_3

Thus, the number of moles of Fe_2O_3  produced will be, 0.241 moles.

6 0
2 years ago
Property of a substance
Scrat [10]

There are many properties to substances.

I'll list some examples below:

  • Mass
  • Volume
  • Density
  • Conductivity
  • Malleability
  • Boiling point
  • Melting point
  • Heat capacity

Hope this helps! :3

8 0
2 years ago
The game of kickball begins with the ball being rolled toward a player. The player then kicks the ball across the field. What is
hammer [34]

Answer:

C. The Speed of the ball depends on the force used to kick it.

Explanation:

6 0
2 years ago
Read 2 more answers
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