You have to find the stoichiometric ratio between AlCl₃ and BaCl₂. The common element between them is Cl. So, the ratio of Cl in BaCl₂ to AlCl₃ is 2/3. The molar mass of AlCl₃ is 133.34 g/mol. The solution is as follows:
Mass of AlCl₃ = (6 mol BaCl₂)(2 mol Cl/1 mol BaCl₂)(1 mol AlCl₃/3 mol Cl)(133.34 g/mol) = 533.36 g AlCl₃
According to the <span> chart represented above, I have determined the pair of atoms which has the greatest polarit and I am pretty sure that it is the first option from the scale :</span>A. Al-Si. I consider this to be correct due to their incredible difference <span>difference in electronegativity.
Hope it helps!</span>
Answer: gas particles that are in constant motion and exhibit perfectly elastic collisions
Explanation:
Answer:there is visible blue black coloration
Explanation:starch is a polysaccharide,it is composed of only glucose combined by glycosidic bonds.starch is majorly an insoluble carbonhydrate.
Starch consist of two distinguishable polysaccharide fraction namely amylose and amylopectin.
The iodine test is used to check for the presence of starch.
It gives a blue black coloration for amylose which is present in potato.
But in amylopectin,it gives a reddish coloration.
Avagadro's number is just a measurement. One mole is 6.022 X 10^23 of anything - atoms, molecules, marbles... anything.
<span>1) If one mole = 6.022 X 10^23, then 8.00mol of H2S is: </span>
<span>(3.00mol H2S) (6.022 X 10^23 molecules H2S / 1 mol H2S) = 1.8060 X 10^24 molecules H2S. </span>
<span>Rounded to 3 sig figs =1.81 X 10^24 molecules H2S
</span>part2.
<span> This one uses moles in the stoichiometric sense as well as the measurement. One formula unit of MgCl2 contains 1 mole Mg and 2 moles Cl. </span>
<span>First, figure out how many moles of formula units there are. </span>
(1.81 X 10^24 FU's) (1mol MgCl2 / 6.022 X 10^23 FU's) = 3.0056mol MgCl2.
<span>Now, we know that there are 2 moles of Cl in every mole of MgCl2 (2 Cl atoms in every unit of MgCl2). From this we can determine how many moles of Cl atoms there are: </span>
<span>(3.0056mol MgCl2) (2mol Cl atoms / 1mol MgCl2) = 6.0112mol Cl atoms. </span>
<span>Now round to 3 sig figs = 10.0mol Cl atoms</span>
