In a equinox, around 20 March and 23 September
Answer:
rA = 0.60 M/s
rC = 0.90 M/s
Explanation:
Let's consider the following reaction:
2 A+B ⇒ 3 C
The rate of each substance can be calculated like the change in its concentration divided by the change in time. Given the rate must always be positive, we add a minus sign before the reactants change in concentration.
![rA=-\frac{\Delta[A] }{\Delta t}](https://tex.z-dn.net/?f=rA%3D-%5Cfrac%7B%5CDelta%5BA%5D%20%7D%7B%5CDelta%20t%7D)
![rB=-\frac{\Delta[B] }{\Delta t}](https://tex.z-dn.net/?f=rB%3D-%5Cfrac%7B%5CDelta%5BB%5D%20%7D%7B%5CDelta%20t%7D)
![rC=\frac{\Delta[C] }{\Delta t}](https://tex.z-dn.net/?f=rC%3D%5Cfrac%7B%5CDelta%5BC%5D%20%7D%7B%5CDelta%20t%7D)
The rate of the reaction is equal to the rate of each substance divided by its stoichiometric coefficient.

The rate of disappearance of B is 0.30 M/s.
The rate of disappearance of A is:

The rate of appearance of C is:

Yes, the more decimal places in a number mean that it is more accurate :3
Magnesium, because it is responsible for more than 300 biochemical reactions and because it’s a solid.
The mass of Ce(NO3)₄ that will be needed to create the solution was 24.16 g (in grams).
<h3>
What exactly is the solution?</h3>
A homogenous mixture with one or even more solutes that have been dissolved in the solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent. To create a homogenous mixture, a component must dissolve in a solvent.
<h3>
What is an illustration of a solution?</h3>
One nanometer or smaller particles are referred to as a solution in a homogeneous mixture made up of two or more components. There are many different types of solutions, including sugar and salt solutions and fizzy water. Each component shows up as a different phase in a solution.
<h3>
Briefing:</h3>
Mole of Ce(NO₃)₄ = 0.06225 mole
Molar of Ce(NO₃)₄ = 140.12 + 4[14 + (16×3)]
= 140.12 + 4[14 + 48]
= 140.12 + 4[62]
= 140.12 + 248
= 388.12 g/mol
Mass of Ce(NO₃)₄ = 0.06225 × 388.12
Mass of Ce(NO₃)₄ = 24.16 g
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