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andrew11 [14]
3 years ago
11

Wilma can mow a lawn in 80 minutes. Rocky can mow the same lawn in 120 minutes. Construct an equation that would allow you to de

termine how long it would take them to mow 2 lawns if they worked together. Use t to represent the number of minutes they work.
Physics
1 answer:
xeze [42]3 years ago
5 0

Answer:

t = 96 minutes

Explanation:

Time to mow 1 lawn by Wilma is 80 minutes

so work done in 1 minute by Wilma is given as

W_1 = \frac{1}{80}

Similarly Rocky mow same lawn in 120 minute

so work done in 1 minute by Rocky is given as

W_2 = \frac{1}{120}

now we know that they both worked by "t" time

so total work performed by them

W = \frac{t}{80} + \frac{t}{120}

they both mow 2 lawns then it is given as

2 = (\frac{1}{80} + \frac{1}{120})t

t = 96 minutes

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A 2,700-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the colli
Leto [7]

Answer:

6200 J

Explanation:

Momentum is conserved.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

The car is initially stationary.  The truck and car stick together after the collision, so they have the same final velocity.  Therefore:

m₁ u₁ = (m₁ + m₂) v

Solving for the truck's initial velocity:

(2700 kg) u = (2700 kg + 1000 kg) (3 m/s)

u = 4.11 m/s

The change in kinetic energy is therefore:

ΔKE = ½ (m₁ + m₂) v² − ½ m₁ u²

ΔKE = ½ (2700 kg + 1000 kg) (3 m/s)² − ½ (2700 kg) (4.11 m/s)²

ΔKE = -6200 J

6200 J of kinetic energy is "lost".

3 0
3 years ago
a scale model of the solar system where 50 cm represents 1.0x10 to the fifth km is actual distance what would be the dimension o
Fofino [41]

The distance between Mars and the Sun in the scale model would be 1140 m

Explanation:

In this scale model, we have:

x_1 = 50 cm represents an actual distance of

d_1 = 1.0\cdot 10^5 km

The actual distance between Mars and the Sun is 228 million km, therefore

d_2=228\cdot 10^6 km

On the scale model, this would corresponds to a distance of x_2.

Therefore, we can write the following proportion:

\frac{x_1}{d_1}=\frac{x_2}{d_2}

And solving for x_2, we find:

x_2=\frac{x_1 d_2}{d_1}=\frac{(50)(228\cdot 10^6)}{1\cdot 10^5}=1.14\cdot 10^5 cm = 1140 m

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

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