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Eddi Din [679]
1 year ago
5

A simple pendulum of length 1.5m has a bob of mass 2.0kg. State the formula for the period of small oscillations and evaluate it

in this case. (2.43s)​
Physics
1 answer:
Shalnov [3]1 year ago
4 0

A simple pendulum of length 1.5m has a bob of mass of 2.0kg, then the period for the small oscillations would be 2.456 s.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,

f = 1/T

As given in the problem A simple pendulum of length 1.5m has a bob of mass of 2.0kg.

The formula for the time period for the pendulum,

T = 2π√L/g

  =2π√1.5/9.81

  =2.456 s

Thus, the period for the small oscillations would be 2.456 s.

Learn more about frequency from here,

brainly.com/question/14316711

#SPJ1

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Explanation:

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