Question

Ammonia is a principal nitrogen fertilizer. It is prepared by the reaction between hydrogen and nitrogen. 3H2(g) + N2(g) → 2NH3(g) In a particular reaction, 8.00 moles of NH3 were produced. How many moles of H2 and how many moles of N2 were reacted to produce this amount of NH3?

Answer 1

Answer:

Explanation:

The equation of the reaction is given as:

             3H₂ + N₂ → 2NH₃

Given parameters:

Number of moles of NH₃ = 8moles

Number of moles of H₂ = ?

Number of moles of N₂ = ?

Solution

From the balanced reaction equation, we can establish some mole ratios that would help solve the problem:

 To find the number of moles of H₂;

      The equation shows that:

              2 moles of NH₃ were produced using 3 moles of H₂

therefore: 8 moles of NH₃ will be produced by  $\frac{8 x 3}{2}$ = 12moles

So, 12 moles of hydrogen gas will react to give 8 moles of ammonia.

   To find the number of moles of N₂

 The equation shows that:

       2 moles of NH₃ were produced from 1 mole of N₂

      8 moles of NH₃ would be produced from  $\frac{8 x 1}{2}$ = 4moles of Nitrogen gas

Therefore, 4moles of nitrogen gas would be produced