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olchik [2.2K]
3 years ago
10

ryan wants to identify an element. which piece of information would best help ryan identify the element? a. how many neutrons th

e element has b. how many electrons the element has c. how many protons the element has d. what charge the element ha
Chemistry
2 answers:
Alex73 [517]3 years ago
7 0
The piece of information that Ryan can use to best identify an element is C. How many protons the element has.
xxTIMURxx [149]3 years ago
7 0

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

There are 3 subatomic particles: Neutrons, protons and electrons.

  1. Neutrons: These particles does not carry any charge and are located inside the nucleus.
  2. Protons: These particles carry positive charge and are also located inside the nucleus.
  3. Electrons: These particles carry negative charge and are found around the nucleus in the orbits. If an element looses 1 electron, it will carry positive charge and if an element gains 1 electron, it will carry a negative charge.

Element is identified by its atomic number. Atomic number is defined as the number of protons or number of electrons.

If one, identifies the number of protons, then the element is easily identified. Electrons on the other hand are easy to remove or add, so it is not convenient to use the number of electrons in identifying the element.

Hence, the correct answer is Option c.

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If an element has 1 valence electrons, how many dots will be in the elements dot diagram?
gayaneshka [121]
The answer is one dot.

The number of dots an element has represented in the diagram, indicates how many valence eletrons( which is the number of electrons in the most exterior energy level of an atom or ion) the element has. So, 1 valence eletron equals one dot.

4 0
3 years ago
Read 2 more answers
URGENT!!! What is the balanced form of this equation?
Ostrovityanka [42]

Explanation: This is a reaction of oxidation of H_2O_2 in the presence of acidified KMnO_4. Acidified KMnO_4 is a strong oxidizing agent.

To balance out the H^+ on the reactant side, we write H_2O on the product side.

Balancing out the following reaction gives us:

2MnO_4^-+6H^++5H_2O_2\rightarrow 2Mn^{2+}+8H_2O+5O_2

5 0
3 years ago
How many grams of phosphorus are in a sample of Ca3(PO4)2 that contains 50.0 g of calcium? Answer: ________ grams of phosphorus.
wel

<u>Answer:</u> The mass of phosphorus that is present for given amount of calcium is 28.53 g.

<u>Explanation:</u>

We are given:

Mass of calcium = 50 grams

The chemical formula of calcium phosphate is Ca_3(PO_4)_2

Molar mass of calcium = 40 g/mol

Molar mass of phosphorus = 31 g/mol

In 1 mole of calcium phosphate, 120 grams of calcium is combining with 62 grams of phosphorus.

So, 50 grams of calcium will combine with = \frac{62}{120}\times 50=28.53g of phosphorus.

Hence, the mass of phosphorus that is present for given amount of calcium is 28.53 g.

6 0
3 years ago
Two samples of a compound containing elements a and b are decomposed. the first sample produces 15 g of a and 35 g of
Alborosie

According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.

The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.

Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases

\frac{a}{b}=\frac{15}{35}=\frac{10}{y}

rearranging,

y=\frac{10\times 35}{15}=23.3

Thus, mass of b produced will be 23.3 g.

3 0
3 years ago
PLEASE HELP ITS DUE TODAY!
Yuri [45]

Answer:

At one atmosphere and twenty-five degrees Celsius, could you turn it into a liquid by cooling it down? Um, and the key here is that the triple point eyes that minus fifty six point six degrees Celsius and it's at five point eleven ATMs. So at one atmospheric pressure, there's no way that you're ever going to reach the liquid days. So the first part of this question is the answer The answer to the first part of a question is no. How could you instead make the liquid at twenty-five degrees Celsius? Well, the critical point is at thirty-one point one degrees Celsius. So you know, if you're twenty-five, if you increase the pressure instead, you will briefly by it, be able to form a liquid. And if you continue Teo, you know, increase the pressure eventually form a salad, so increasing the pressure is the second part. If you increase the pressure of co two thirty-seven degrees Celsius, will you ever liquefy? No. Because then, if you're above thirty-one point one degrees Celsius in temperature. You'LL never be able to actually form the liquid. Instead, you'LL only is able Teo obtain supercritical co too, which is really cool thing. You know, they used supercritical sio tu tio decaffeinated coffee without, you know, adding a solvent that you'LL be able to taste, which is really cool. But no, you can't liquefy so two above thirty-one degrees Celsius or below five-point eleven atmospheric pressures anyway, that's how I answer this question. Hope this helped :)

5 0
2 years ago
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