Answer:
abiotic
Explanation:
i think but dont take my word for it
Answer:
Explanation:
Question 1
An arrow weighing 20g shortly after firing has a speed of 50m / s. Calculate the work done by the athlete. What is the potential energy of the elasticity of the tensed string?
mass m = 20g = 20/1000 = 0.02kg
speed v = 50m / s
P.E = K.E = ½mv²
P.E = ½ × 0.02 × 50²
P.E = 25 J
work done = P.E = 25J
Qestion 2
A 80 kg athlete stood on a trampoline with a coefficient of elasticity of k = 2 kN / m. As far as the edge of the trampoline lowers.
force of elasticity
F = -kx
x = F / k
in our case F will be the force of pressure or gravity
F = mg
g is gravitational acceleration, and according to Newton's second law, acceleration is force through mass - unit of force N, unit of mass kg. Acceleration either in m / s ^ 2 or N / kg
F = 80kg * 10N / kg = 800 N
x = 800N / -2000N = -0.4
The trampoline will lower, so from the level by 0.4 meters and hence this minus
Answer:
Approximately .
Explanation:
Consider two objects of mass and . Let denote the distance between the center of mass of each object. Let denote the gravitational constant. (.)
By Newton's Law of Universal Gravitation, the size of gravitational attraction between these two objects would be:
.
In this question, and are the mass of the two planets. The distance between the two planets is (approximately the same as the distance between the center of mass of planet Earth and the center of mass of Mars.)
Apply Newton's Law of Universal Gravitation to find the size of gravitational attraction between the two planets:
.
Since , the size of gravitational attraction between the two planets would be approximately .
Answer:
Explanation:
We know that the work could be calculate dby:
W =
where is the component of the force in the direction of the
displacement. and d is the displacement.
So, the total work () is:
Where is the force done by the first tugboat, is the angle of the force, d is the displacement and is the force done by the second tugboat.