To solve this exercise it is necessary to apply the equations related to the magnetic moment, that is, the amount of force that an image can exert on the electric currents and the torque that a magnetic field exerts on them.
The diple moment associated with an iron bar is given by,
Where,
Dipole momento associated with an Atom
N = Number of atoms
y previously given in the problem and its value is 2.8*10^{-23}J/T
The number of the atoms N, can be calculated as,
Where
Density
Molar Mass
A = Area
L = Length
Avogadro number
Then applying the equation about the dipole moment associated with an iron bar we have,
PART B) With the dipole moment we can now calculate the Torque in the system, which is
<em>Note: The angle generated is perpendicular, so it takes 90 ° for the calculation made.</em>
Yes, atoms need to be equal in protons and electrons
Answer:
Explanation:
First of all, let's convert from nanometres to metres, keeping in mind that
So we have:
Now we can convert from metres to centimetres, keeping in mind that
So, we find:
Refer to the diagram shown below.
m = the mass of the object
x = the distance of the object from the equilibrium position at time t.
v = the velocity of the object at time t
a = the acceleration of the object at time t
A = the amplitude ( the maximum distance) of the mass from the equilibrium
position
The oscillatory motion of the object (without damping) is given by
x(t) = A sin(ωt)
where
ω = the circular frequency of the motion
T = the period of the motion so that ω = (2π)/T
The velocity and acceleration are respectively
v(t) = ωA cos(ωt)
a(t) = -ω²A sin(ωt)
In the equilibrium position,
x is zero;
v is maximum;
a is zero.
At the farthest distance (A) from the equilibrium position,
x is maximum;
v is zero;
a is zero.
In the graphs shown, it is assumed (for illustrative purposes) that
A = 1 and T = 1.
