3 years ago

Newton's second law of motion is also known as the law of.......

Physics

1 answer:

OverLord2011 [107]3 years ago

4 0

I think it is force of acceleration but I'm not sure.. hope this helps though!

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QUICK! If i have a 95.6% in my as my grade in that class what is 30% off of that grade?

cluponka [151]

66.92 will be your grade

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3 years ago

Calculate the pressure of water in a will if the deep of the water is 10 m

Bas_tet [7]

Answer:

98,000 pa

Explanation:

The formula for water pressure is as follows:

$pressure = pgh$

Where p is the density of water (in kg/m3), g is the gravitational field strength, and h is the height of the water.

The density of water is 1000kg/m3, the gravitational field strength is 9.8, and the height is 10. Substituting in these values:

$pressure = 1000 \times 9.8 \times 10$

$pressure = 98000$

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1 year ago

Energy in an ecosystem's energy pyramid always flows from __________.

Anna11 [10]

The Answer is B because primary consumers need to get their food from plants.

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3 years ago

Read 2 more answers

The current that charges a capacitor transfers energy that is stored in the capacitor’s electric field. Consider a 2.0 μF capaci

lapo4ka [179]

Answer:

the capacitor voltage is V = 20 V

Explanation:

Given,

Capacitance of the capacitor = 2.0 μF

energy stored = 200 W

time (t) =2.0 μs

Capacitor voltage = ?

$\dfrac{dE}{dt}=200 W$

$E =200\times 2 \times 10^{-6}$

$E =400 \times 10^{-6}\ J$

we know,

$E = \dfrac{1}{2}CV^2$

$V =\sqrt{\dfrac{2E}{C}}$

$V =\sqrt{\dfrac{2\times 400 \times 10^{-6}}{2\times 10^{-6}}}$

$V =\sqrt{400}$

V = 20 V

so , the capacitor voltage is V = 20 V

7 0

2 years ago

A 1.5kg cart moves along a track at 0.20m/s until it hits a fixed bumper at the end of the track. Find the average force exerted

DochEvi [55]

Answer:

Net force will be 4.875 N

Explanation:

We have given mass of the cart m = 1.5 kg

Initial velocity of the cart = 0.2 m/sec

And final velocity of the car = - 0.125 m/sec ( Negative direction is due to opposite direction )

Instant of time $\Delta t=0.1sec$

Change in momentum is given by

$\Delta P=1.5\times (0.2-(-0.125))=1.5\times 0.325=0.4875kgm/sec$

Now force is given by

$F=\frac{\Delta P}{\Delta t}=\frac{0.4875}{0.1}=4.875N$

Net force will be 4.875 N

6 0

2 years ago