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mel-nik [20]
3 years ago
6

Why is the chemistry of actinoids complicated?

Chemistry
1 answer:
gladu [14]3 years ago
8 0

Answer:

Explanation:

Actinoids are the series have 15 element in the periodic table.

Chemistry of actinoids are complicated because of the following reasons.

  • Their outer most orbitals are 6d and 7s but most of the electrons resides in 5f orbitals. These orbitals are most exposed to environment and incoming electron picked up by 5f orbital instead of 6d or 7s orbitals.
  • They are radioactive elements that couldn't be handle in normal condition to study their properties.
  • Their f-orbital can accommodate 14 electrons and they have many variable oxidation state.
  • 5d electron donot contribute in the formation of chemical bonds.
  • They have a very strong tendency to make complexes
  • Most of the actinoides are artificial and are in very minute in amount. they are in very less quantity that is amounts found in nano-grams so are more expensive too and
  • As they are radioactive so their half life is very short and in very less time the decay occur so couldn't be study as upon decay their actual properties changed.

Due to all the above reasons it make difficult for a chemist to study about the chemical properties of actinoids.

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Explanation:

A. 55

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Can someone help please I will give Brainlyiest
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Answer:

See Explanation

Explanation:

moles of NH₃ = 11.9g/17.03 g/mol = 0.699 mole

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Theoretical yield of CN₂OH₄ = (0.349 mole)(60 g/mole) = 20.963 grams

%Yield = Actual Yield/Theoretical Yield x 100%

= 18.5g/20.963g x 100% = 88.25%

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when propene gas (C3H6) is added to bromine liquid, another liquid is produced which has the formula C3H6Br2. what is the chemic
klio [65]

Answer:

C3H6 + Br2 → C3H6Br2

Explanation:

The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:

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We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.

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17) A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with what volume? HI
galina1969 [7]

Answer: A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

Explanation:

Given: M_{1} = 0.20 M,      V_{1} = 15.0 mL

M_{2} = 0.10 M,            V_{2} = ?

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula s follows.

M_{1}V_{1} = M_{2}V_{2}\\0.20 M ]times 15.0 mL = 0.10 M ]times V_{2}\\V_{2} = 30 mL

Thus, we can conclude that a 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

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Answer:

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