First you have a knowledge of bond order which is
B.O=(no. of electrons in bonding orbital - no. of electrons in non-bonding orbital)÷2
Note:
bond strength is directly proportional to bond order.
For oxygen:
B.O=(6-2)/2= 2; after the removal of two electrons(removal occur from non-bonding orbital)
B.O=(6-0)/2= 3 (As B.O increased bond strength increased)
For Nitrogen:
B.O=(6-0)/2= 3; after the removal of two electrons(removal occur from bonding orbital)
B.O=(4-0)/2= 2 (As B.O decreased bond strength decreased)
Explanation:
It can be compromise increasing the threat of a meltdown
A. Outer energy level electrons are shared.
In electrovalent combination, after donating their valence electrons, metallic particles become positively charged; non metallic particles become negatively charged after acquiring extra electrons.
The electrons involved reside in the outermost shells of the atoms.
PeAcE.
Answer:
T = 3206.89 K
Explanation:
Given that,
Number of moles, n = 1.9 moles
Pressure, P = 5 atm
Volume, V = 100 L
We need to find the temperature of the gas. Let the temperature is T. We know that,
PV = nRT
Where
R is gas constant, R = 0.08206 L-atm/mol-K
Put all the values,
So, the temperature of the gas is 3206.89 K.
